我正在使用python创建使用元素和子元素过程的xml文件。我的文件夹中有一个zip文件列表，如下所示：
Retirement_participant-plan_info_v1_getPlankeys_rev1_2021_03_09.zip
Retirement_participant-plan_info_resetcache_secretmanager_rev1_2021_03_09.zip
Retirement_participant-plan_info_v1_mypru_plankeys_rev1_2021_03_09.zip
Retirement_participant-plan_info_resetcache_param_value_rev1_2021_03_09.zip
Retirement_participant-plan_info_resetcache_param_v1_balances_rev1_2021_03_09.zip
我想拆分那些zip文件，得到这样的名称：
Retirement_participant-plan_info_v1_getPlankeys
Retirement_participant-plan_info_resetcache_secretmanager
Retirement_participant-plan_info_v1_mypru_plankeys
Retirement_participant-plan_info_resetcache_param_value
Retirement_participant-plan_info_resetcache_param_v1_balances
PS：我想在从zip文件创建名称时删除_rev1_2021_03_09.zip。
这是我的python代码。它适用于Retirement_participant-plan_info_v1_getPlankeys_rev1_2021_03_09.zip，但如果我的压缩文件名太大，例如Retirement_participant-plan_info_resetcache_param_v1_balances_rev1_2021_03_09.zip，它就不起作用了
Proxies = SubElement(proxy, 'Proxies')
path = "./"
for f in os.listdir(path):
if '.zip' in f:
Proxy = SubElement(Proxies, 'Proxy')
name = SubElement(Proxy, 'name')
fileName = SubElement(Proxy, 'fileName')
a = f.split('_')
name.text = '_'.join(a[:3])
fileName.text = str(f)
您可以通过rev1_进行str.split
>>> filenames
['Retirement_participant-plan_info_v1_getPlankeys_rev1_2021_03_09.zip',
'Retirement_participant-plan_info_resetcache_secretmanager_rev1_2021_03_09.zip',
'Retirement_participant-plan_info_v1_mypru_plankeys_rev1_2021_03_09.zip',
'Retirement_participant-plan_info_resetcache_param_value_rev1_2021_03_09.zip',
'Retirement_participant-plan_info_resetcache_param_v1_balances_rev1_2021_03_09.zip']
>>> names = [fname.split('_rev1_')[0] for fname in filenames]
>>> names
['Retirement_participant-plan_info_v1_getPlankeys',
'Retirement_participant-plan_info_resetcache_secretmanager',
'Retirement_participant-plan_info_v1_mypru_plankeys',
'Retirement_participant-plan_info_resetcache_param_value',
'Retirement_participant-plan_info_resetcache_param_v1_balances']
通过将maxsplit限制为4:，str.rsplit也可以实现这一点
>>> names = [fname.rsplit('_', 4)[0] for fname in filenames]
>>> names
['Retirement_participant-plan_info_v1_getPlankeys',
'Retirement_participant-plan_info_resetcache_secretmanager',
'Retirement_participant-plan_info_v1_mypru_plankeys',
'Retirement_participant-plan_info_resetcache_param_value',
'Retirement_participant-plan_info_resetcache_param_v1_balances']
如果rev和日期始终相同(2021_03_09(，只需将它们替换为空字符串：
filenames = [f.replace("_rev1_2021_03_09.zip", "") for f in os.listdir(path)]