获取模板中的URL时出错-Django

Question

我正试图复制一个电子商务网站，并在它们点击类别的不同链接时显示单独的产品。但是我在获取模板中的url时遇到了问题。

这是我的视图.py：

from django.shortcuts import render, redirect, reverse, get_object_or_404
from django.views import View
from .models import Product, Category
class ProductView(View):
def get(self, request, *args, **kwargs):
products = Product.objects.filter(is_active = True)

context = {
'products': products,
}
return render(request, 'Product/products.html', context)
class ProductDetailView(View):
def get(self, request, slug):
singleproduct = Product.objects.get(slug = slug)
context = {
'singleproduct': singleproduct,
}
return render(request, 'Product/productdetail.html', context)
class eBookView(View):
def get(self, request, catslug):
ebooks = Product.objects.filter(category__category = 'eBooks')
context = {
'ebooks': ebooks
}
return render(request, 'Product/ebooks.html', context)
class IllustrationView(View):
def get(self, request, catslug):
illustration = Product.objects.filter(category__category = 'Illustration')
context = {
'illustration': illustration
}
return render(request, 'Product/downloadillustration.html', context)
class PhotosView(View):
def get(self, request, catslug):
photos = Product.objects.filter(category__category = 'Photos')
context = {
'photos': photos
}
return render(request, 'Product/photos.html', context)
class WebsiteTemplatesView(View):
def get(self, request, catslug):
website = Product.objects.filter(category__category = 'Website Templates')
context = {
'website': website
}
return render(request, 'Product/websitetemplates.html', context)

这是我的urls.py：

from django.urls import path
from .views import ProductView, ProductDetailView, eBookView, IllustrationView, PhotosView, 
WebsiteTemplatesView
urlpatterns = [
path('', ProductView.as_view(), name = 'products'),
path('<slug:slug>/', ProductDetailView.as_view(), name = 'product-detail'),
path('ebook/<slug:catslug>/', eBookView.as_view(), name = 'ebooks'),
path('illustration/<slug:catslug>/', IllustrationView.as_view(), name = 'illustration'),
path('photos/<slug:catslug>/', PhotosView.as_view(), name = 'photos'),
path('website-templates/<slug:catslug>', WebsiteTemplatesView.as_view(), name = 'website- 

模板’(，]

这是模板：

{% extends 'Base/base.html %}
{% block content %}
<a href="{% url 'ebook' catslug=instance.catslug %}</a>
{% endblock %}

我想在导航栏中添加类别的URL，但在导航栏添加类别的url时显示了一个错误。

Answer 1

这样更正模板：

{% extends 'Base/base.html %}
{% block content %}
<a href="{% url 'ebooks' instance.catslug %}>Category</a>
{% endblock %}

注意：使用{% url %}标记时，请指定在urls.py文件中定义的路径的名称，也不必指定url参数的名称。

Answer 2

在您的路径中，您已经给定了name=ebooks，因此您可以在模板中使用该名称。

您已经编写了ebook，应该是ebooks。此外，您的a标记格式不正确。

{% extends 'Base/base.html %}
{% block content %}
<a href="{% url 'ebooks' instance.catslug %}>Category</a>
{% endblock %}