如果重复出现异常，则更改用户输入语句

Question

我正在尝试用python 3编写一个hang-man游戏。我选择一名玩家输入密码，并进行检查，以确保没有数字、特殊字符等。如果当前玩家试图违反这些规则，我希望能够给其他球员选择密码的机会。然后我希望它一直交替，直到有人输入符合标准的单词。我现在拥有的。。。

word_to_guess = input(First_player + " has been randomly chosen to pick a word! Please type it in now with no numbers, spaces or special characters: ").lower()
while True:
if word_to_guess.isalpha():
break
word_to_guess = input("OK, " + Second_player + ", since " + First_player + " can't follow the rules, you try it. Again, no numbers, spaces or special characters: ").lower()

因此，如果第一个玩家得到了它，我们继续前进，如果第一位玩家失败了，第二位玩家得到了，我们继续前行，但如果他们都失败了，编写的代码将继续让玩家2选择单词。我基本上只是想把"；第一_；以及"；第二层；最后一句话中的可变位置，每次重复。有什么想法吗？

Answer 1

它认为第5行中硬编码的First_player和Second_player可能会让你有点失望。

word_to_guess = input(First_player + " has been randomly chosen to pick a word! Please type it in now with no numbers, spaces or special characters: ").lower()
turn_player = First_player
last_player = Second_player
while True:
if word_to_guess.isalpha():
break
turn_player, last_player = last_player, turn_player
word_to_guess = input("OK, " + turn_player + ", since " + last_player + " can't follow the rules, you try it. Again, no numbers, spaces or special characters: ").lower()

Answer 2

我认为您可以使用flag变量，它将显示轮到谁是

word_to_guess = input(First_player + " has been randomly chosen to pick a word! Please type it in now with no numbers, spaces or special characters: ").lower()
is_first_player_turn = False
while True:
if is_first_player_turn:
#First player's turn
else:
#Second player's turn
is_first_player_turn = not is_first_player_turn