df <- data.frame(
"Domain" = c("Euka"),
"Kingdom" = c("An","Plan"),
"Division" = c("20181121","20181128","20181203"),
"Species" = c("20181115_AG25_MAGH_50_A05_CGT.TXT","20181122_AG25_MAGH_50_C05_CGT.ARR",
"20181115_AG25_MAGH_50_G05_CGT.TXT","20181124_AG25_MAGH_50_G45_CGT.TXT",
"20181204_AG25_MAGH_50_G05_CGT.ARR","20181205_AG25_MAGH_50_G45_CGT.TXT",
"20181207_AG25_MAGH_50_T05_CGT.ARR","20181215_AG25_MAGH_50_F45_CGT.TXT",
"20181223_AG25_MAGH_50_R07_CGT.GGI","20181225_TW77_MAGH_33_L06_CGT.ARR",
"20181226_TW77_MAGH_33_S07_CGT.ARR","20181227_TW77_MAGH_33_C06_CGT.TXT")
)
我想总结一下
Division |
---|
Total_TXT |
Total_ARR |
Total_GGI |
这里有一个tidyverse
选项,我们使用count
来获得每组的总数,然后我们可以使用pivot_wider
将其转换为宽格式。
library(tidyverse)
df %>%
group_by(gr = Division) %>%
count(Division = str_replace_all(Species, '.*\.', '')) %>%
pivot_wider(names_from = "gr", values_from = "n", values_fill = 0) %>%
mutate(Division = paste0("Total_", Division))
输出
Division `20181121` `20181128` `20181203`
<chr> <int> <int> <int>
1 Total_ARR 2 3 0
2 Total_TXT 2 1 3
3 Total_GGI 0 0 1
或者这里有一个data.table
选项:
library(data.table)
df <-
setDT(df)[, .N, by = .(cn = Division, Division = str_replace_all(Species, '.*\.', ''))]
dcast(df,
paste0("Total_", Division) ~ cn,
value.var = "N",
fill = 0)
我们需要从Species中提取最后三个字符:
x <- nchar(df$Species)
rowlbl <- substr(df$Species, x-2, x)
table(rowlbl, df$Division)
# rowlbl 20181121 20181128 20181203
# ARR 2 3 0
# GGI 0 0 1
# TXT 2 1 3
Base R一行
table(sub('.*\.', '', df$Species), df$Division)
# 20181121 20181128 20181203
# ARR 2 3 0
# GGI 0 0 1
# TXT 2 1 3
解释:
sub
删除所有内容,直到最后一个返回的"."
sub('.*\.', '', df$Species)
#[1] "TXT" "ARR" "TXT" "TXT" "ARR" "TXT" "ARR" "TXT" "GGI" "ARR" "ARR" "TXT"
然后将其用于具有Division
值的table
中。
sub
也可以替换为tools::file_ext
。
table(tools::file_ext(df$Species), df$Division)