基于包含字符串的元素将列表拆分为子列表

Question

我知道有一个简单的解决方案，但我似乎找不到。

我想根据只包含字符串的元素来拆分列表。

在这种情况下；存储"；

from itertools import groupby
test_string = ['Store465', 'Steve', '145658', '125', 'Brad', '457958', '200', 'Store678', 'John', '30122', '898', '123', 'O', 'Joe', '36789', '123', 'U', ' 456']
# I've tried 
test_string[:] = [x for x in test_string if "Store" not in x]
print(test_string)
# but that will just remove the  Store elements
# ['Steve', '145658', '125', 'Brad', '457958', '200', 'John', '30122', '898', '123', 'O', 'Joe', '36789', '123', 'U', ' 456']
# and
test_result = [list(g) for k,g in groupby(test_string,lambda x:x if "Store" not in x) if not k]
# This creates an error. 
#
#   File "<input>", line 13
#     test_result = [list(g) for k,g in groupby(test_string,lambda x:x if "Store" not in x) if not k]
#                                                                                         ^
# SyntaxError: invalid syntax

我一直在stackoverflow和谷歌上试图找到正确的语法或过程，但没有成功。我想要的输出是

[['Store465', 'Steve', '145658', '125', 'Brad', '457958', '200'], ['Store678', 'John', '30122', '898', '123', 'O', 'Joe', '36789', '123', 'U', ' 456']]

Answer 1

要通过列表中Store的出现来分割列表，可以执行以下操作：

test_string = ['Store465', 'Steve', '145658', '125', 'Brad', '457958', '200', 'Store678', 'John', '30122', '898', '123', 'O', 'Joe', '36789', '123', 'U', ' 456']
test_loop = []
for item in test_string:
if 'Store' in item: # create a new list to store all of the elements after store mentioned inside of the outer list
test_loop.append([item])
else:  # add elements after store into the last list and before the next mention of Store
test_loop[-1].append(item)
print(test_loop)

它给出：

[['Store465', 'Steve', '145658', '125', 'Brad', '457958', '200'], ['Store678', 'John', '30122', '898', '123', 'O', 'Joe', '36789', '123', 'U', ' 456']]