我正在使用ncftpput
将图像上传到ftp服务器。该脚本的一个例子是
# destination. origin
ncftpput -R ftp_server icon_d2/cape_cin ./cape_cin_*.png
ncftpput -R ftp_server icon_d2/t_v_pres ./t_v_pres_*.png
ncftpput -R ftp_server icon_d2/it/cape_cin ./it/cape_cin_*.png
ncftpput -R ftp_server icon_d2/it/t_v_pres ./it/t_v_pres_*.png
我正试图用GNUparallel
并行化,但我很难将参数传递给ncftpput
。我知道自己做错了什么,但不知怎么找不到解决办法。
如果我构建了我需要上传的数组
images_output=("cape_cin" "t_v_pres")
# suffix for naming
projections_output=("" "it/")
# remote folder on server
projections_output_folder=("icon_d2" "icon_d2/it")
# Create a list of all the images to upload
upload_elements=()
for i in "${!projections_output[@]}"; do
for j in "${images_output[@]}"; do
upload_elements+=("${projections_output_folder[$i]}/${j} ./${projections_output[$i]}${j}_*.png")
done
done
然后我可以像这个一样串行上传
for k in "${upload_elements[@]}"; do
ncftpput -R ftp_server ${k}
done
当使用parallel
时,我使用colsep
来分隔参数
parallel -j 5 --colsep ' ' ncftpput -R ftp_server ::: "${upload_elements[@]}"
但CCD_ 6给出了一个错误,告诉我它没有理解传递的参数的结构。我做错了什么?
尝试:
parallel -j 5 --colsep ' ' eval ncftpput -R ftp_server ::: "${upload_elements[@]}"
这应该完全相同:
for k in "${upload_elements[@]}"; do
echo ncftpput -R ftp_server ${k}
done | parallel -j 5