有没有办法让鼠标事件完全忽略PyQt5中的窗口

Question

我尝试过使用setAttribute(Qt.Qt.WA_TransparentForMouseEvents)，但鼠标也无法穿透Qtwindow。

我想让鼠标事件穿透Qtwindow，就像我在Windows10桌面中的Qtwindows上点击鼠标右键一样，然后它会触发win10上下文菜单。

Answer 1

透明窗口是否适合您的需求？

from PyQt5 import QtCore, QtWidgets, QtGui

class Overlay(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.setAttribute(QtCore.Qt.WA_TransparentForMouseEvents)
self.setAttribute(QtCore.Qt.WA_TranslucentBackground, True)
self.setWindowFlags(QtCore.Qt.FramelessWindowHint)
layout = QtWidgets.QHBoxLayout(self)
label = QtWidgets.QLabel('Transparent and propagating')
label.setFont(QtGui.QFont('Arial', 26))
label.setStyleSheet("background-color : white")
layout.addWidget(label)
self.show()

if __name__ == '__main__':
app = QtWidgets.QApplication([])
form = Overlay()
app.exec_()

我试图找到一种直接将点击传输到桌面的方法。最相关的问题给了我一些想法，但最终我没能让它发挥作用，点击永远不会到达桌面。也许你仍然可以从中得到一些想法：

from PyQt5 import QtWidgets, QtGui
import win32api, win32con
from ctypes import windll

class Overlay(QtWidgets.QWidget):
def __init__(self):
super().__init__()
layout = QtWidgets.QHBoxLayout(self)
label = QtWidgets.QLabel('Click to Desktop')
label.setFont(QtGui.QFont('Arial', 26))
label.setStyleSheet("background-color : white")
layout.addWidget(label)
# make window partially transparent to see where you are clicking
self.setWindowOpacity(0.5)
# get handle to desktop as described in linked question
hProgman = windll.User32.FindWindowW("Progman", 0)
hFolder = windll.User32.FindWindowExW(hProgman, 0, "SHELLDLL_DefView", 0)
self.desktop = windll.User32.FindWindowExW(hFolder, 0, "SysListView32", 0)
self.show()
def mousePressEvent(self, event):
# catch mouse event to route it to desktop
x = event.globalPos().x()
y = event.globalPos().y()
lParam = win32api.MAKELONG(x, y)
# left click on desktop (left button down + up, => should be replaced by event.button() pseudo switch case once working)
windll.User32.SendInput(self.desktop, win32con.WM_LBUTTONDOWN, win32con.MK_LBUTTON, lParam)
windll.User32.SendInput(self.desktop, win32con.WM_LBUTTONUP, 0, lParam)
# display position for debugging (position gets displayed, but nothing gets clicked)
print(f'clicked on desktop at position {x} and {y}')

if __name__ == '__main__':
app = QtWidgets.QApplication([])
form = Overlay()
app.exec_()

Answer 2

class main(QWidget):
def __init__(self):
super().__init__()
self.setWindowFlags(Qt.Popup|Qt.WindowDoesNotAcceptFocus|Qt.WindowTransparentForInput)
self.setAttribute(Qt.WA_AlwaysStackOnTop, True)