如何在单词后和字符前获取列表



我现在有这个字符串,我想提取出这些名字,例如Garet Hayes、Ronald Allen等。

Executives
Garet Hayes - Director, Public Relations
Ronald Allen - Chief Executive Officer
Gilbert Danielson - Executive Vice President and Chief Financial Officer
Steven Michaels - President
John Robinson - Executive Vice President and President and Chief Executive Officer, Progressive Finance Holdings LLC

我可以通过以下代码提取第一个名字Garet Hayes:

def partiesExtractor(doc):
executives = []
executives.append(doc[doc.lower().index('executives') + len('executives') + 1 : doc.index(' -')])
return executives

但我觉得应该有一种更有效的方法,即使只是获得第一个名字,更不用说第二个或列表的其余部分了。我该怎么做?

您需要将内容分成几行,然后每行都用短划线分割,并保留第一部分

def partiesExtractor(doc):
executives = []
for line in doc.splitlines()[1:]:
executives.append(line.split("-")[0].strip())
return executives
# return [line.split("-")[0].strip() for line in doc.splitlines()[1:]] # list-comprenhension

text = """Executives
Garet Hayes - Director, Public Relations
Ronald Allen - Chief Executive Officer
Gilbert Danielson - Executive Vice President and Chief Financial Officer
Steven Michaels - President
John Robinson - Executive Vice President and President and Chief Executive 
Officer, Progressive Finance Holdings LLC"""
print(partiesExtractor(text))  # ['Garet Hayes', 'Ronald Allen', 'Gilbert Danielson', 'Steven Michaels', 'John Robinson']

你也可以使用regex

def partiesExtractor(doc):
return re.findall("^[A-Z][a-z]+ [A-Z][a-z]+", doc, flags=re.MULTILINE)

类似于@azro使用列表理解的解决方案:

def partiesExtractor(doc):
return [line.split(" - ")[0] for line in doc.split("n")[1:]]

使用正则表达式:


import re
s = '''Executives
Garet Hayes - Director, Public Relations
Ronald Allen - Chief Executive Officer
Gilbert Danielson - Executive Vice President and Chief Financial Officer
Steven Michaels - President
John Robinson - Executive Vice President and President and Chief Executive Officer, Progressive Finance Holdings LLC'''
reg = '(w+sw+)s-s'
names = re.findall(reg,s)
print(names)
['Garet Hayes', 'Ronald Allen', 'Gilbert Danielson', 'Steven Michaels', 'John Robinson']

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