使用django CreateView更新onetoone

Question

我使用CreateView来更新我的Person模型。该模型与address有一对一的关系。当尝试更新Person模型时，我无法同时更新address模型。它只给我一个现有地址的列表，但没有办法添加一个新地址。我可以看到，这是可能的管理。这是可能的，在CreateView?

model.py:

class Person(Model):

fname=CharField(default="missing",max_length=100)
lname=CharField(default="missing",max_length=100)
mobil=PhoneField(default='9999999999')
mail=EmailField(default='[e-mail]')
padress=OneToOneField(Adress,on_delete=CASCADE,primary_key=True)

def __str__(self):
return self.fname

class Meta:
ordering=('fname','lname')

class Adress(Model):

street=CharField(default='missing',max_length=100)
snumb=CharField(default='missing',max_length=15)
town=CharField(default='missing',max_length=100)
postn=CharField(default='99999',max_length=5,validators=[postnvali])

def __str__(self):
return self.town

class Meta:
ordering=('street','town')
view.py
class PCreate(CreateView):

template_name='kammem/create.html'
model=Person
fields=['fname','lname','mobil','mail','padress']
success_url=reverse_lazy('forl')
url.py
path('pcreate/',PCreate.as_view(),name='pcreate'),
template: 
{% extends 'edit2.html' %}

{% block add %}
<form method="post">{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Save">
</form>
{% endblock %}
any suggestions?
ok, here is an update. I can save both instances and also create the relation. But I still can't exit the function, please look at the following:
class PCreate2(CreateView):

form_class=PersonForm
template_name='kabmmem/create.html'
success_url=reverse_lazy('forl')
def form_valid(self,form):
# create address and person
street = form.cleaned_data['street']
snumb = form.cleaned_data['snumb']
town = form.cleaned_data['town']
postn = form.cleaned_data['postn']
fname = form.cleaned_data['fname']
lname = form.cleaned_data['lname']
mobil = form.cleaned_data['mobil']
mail = form.cleaned_data['mail']
a=Adress.objects.create(street=street,snumb=snumb,town=town,postn=postn)
pe=Person.objects.create(fname=fname,lname=lname,mobil=mobil,mail=mail,padress=a)
return HttpResponseRedirect(self.get_success_url())

返回语句给出:AttributeError: 'NoneType'对象没有属性'dict'

所以，我还是迷路了…

返回语句

Answer 1

您可以设置PersonFormModelForm并在其中定义地址字段。将此表单分配给视图的form_class属性将确保地址字段可用于在页面上进行编辑。

表单经过验证后，您必须手动创建地址对象并将其分配给表单的padress字段。您可以在视图的form_valid方法中执行此操作。

forms.py

from django import forms
class PersonForm(forms.ModelForm):
street=forms.CharField(max_length=100)
snumb=forms.CharField(max_length=15)
town=forms.CharField(max_length=100)
postn = forms.CharField(max_length=5, validators=[postnvali])
class Meta:
model = Person
exclude = ['padress']

views.py

class PCreate(CreateView):

form_class=PersonForm
template_name='kammem/create.html'
success_url=reverse_lazy('forl')
def form_valid(self, form):
# create address
street = form.cleaned_data['street']
snumb = form.cleaned_data['snumb']
town = form.cleaned_data['town']
postn = form.cleaned_data['postn']
address = Address.objects.create(street=street, snumb=snumb, town=town, postn=postn)
# get the response
response = super().form_valid(form)
# assign the address to the person object
self.object.padress = address
self.object.save()
# return the response
return response

Answer 2

好的，所以经过大量的研究，终于找到了一个解决方案。我只是在CreateView函数中设置了两个表，并返回了成功url。这是一个丑陋的解决方案。如果有人知道更好的解决办法，请告诉我。这是一种更新外部字段的常见模式，但是文档中很少提到

views.py:

class PCreate2(CreateView):

form_class=PersonForm
template_name='kammem/create.html'
def form_valid(self,form):
# create address
street = form.cleaned_data['street']
snumb = form.cleaned_data['snumb']
town = form.cleaned_data['town']
postn = form.cleaned_data['postn']
fname = form.cleaned_data['fname']
lname = form.cleaned_data['lname']
mobil = form.cleaned_data['mobil']
mail = form.cleaned_data['mail']
a=Adress.objects.create(street=street,snumb=snumb,town=town,postn=postn)
pe=Person.objects.create(fname=fname,lname=lname,mobil=mobil,mail=mail,padress=a)
return HttpResponseRedirect(reverse_lazy('personer'))