Regex捕获重复组上不需要的字符

Question

组的后续捕获包括逗号或右括号。

regex:

(?<name1>??$.*)s((?<type1>w+)s(?<conv>w+)s(?<name2>w+:?:?)+<(?<type2>[ws]+)>((?<args>.+?(?=[,)]))+)

输入:

??$PlotBarGroups@C@ImPlot@@YAXQBQBDPBCHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<signed char>(char const * const * const,signed char const *,int,int,double,double,int))
??$PlotBarGroups@E@ImPlot@@YAXQBQBDPBEHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<unsigned char>(char const * const * const,unsigned char const *,int,int,double,double,int))
??$PlotBarGroups@F@ImPlot@@YAXQBQBDPBFHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<short>(char const * const * const,short const *,int,int,double,double,int))
??$PlotBarGroups@G@ImPlot@@YAXQBQBDPBGHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<unsigned short>(char const * const * const,unsigned short const *,int,int,double,double,int))
??$PlotBarGroups@H@ImPlot@@YAXQBQBDPBHHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<int>(char const * const * const,int const *,int,int,double,double,int))
??$PlotBarGroups@I@ImPlot@@YAXQBQBDPBIHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<unsigned int>(char const * const * const,unsigned int const *,int,int,double,double,int))
??$PlotBarGroups@M@ImPlot@@YAXQBQBDPBMHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<float>(char const * const * const,float const *,int,int,double,double,int))
??$PlotBarGroups@N@ImPlot@@YAXQBQBDPBNHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<double>(char const * const * const,double const *,int,int,double,double,int))
??$PlotBarGroups@_J@ImPlot@@YAXQBQBDPB_JHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<__int64>(char const * const * const,__int64 const *,int,int,double,double,int))
??$PlotBarGroups@_K@ImPlot@@YAXQBQBDPB_KHHNNH@Z (void __cdecl ImPlot::PlotBarGroups<unsigned __int64>(char const * const * const,unsigned __int64 const *,int,int,double,double,int))

实际结果:

signed char
char const * const * const
,signed char const *
,int
,int
,double
,double
,int
)

预期结果:

signed char
char const * const * const
signed char const *
int
int
double
double
int

在线样本:

https://regex101.com/r/Fkyk4P/1

问题:

如何不捕获这些逗号和右括号?

Answer 1

你可以试试这个regex:

(?<name1>?{0,2}$.*)s((?<type1>w+)s(?<conv>w+)s(?<name2>w+:{0,2})+<(?<type2>[ws]+)>((?: *(?<args>[^,)]+)[,)])+

更新的RegEx Demo

注意最后一个重复捕获组:

(?: *(?<args>[^,)]+)[,)])+

匹配1+个非逗号、非)字符，后面必须跟,或)。

或者如果我们想让这个正则表达式更严格，那么使用:

(?<name1>?{0,2}$.*)s((?<type1>w+)s(?<conv>w+)s(?<name2>w+:{0,2})+<(?<type2>[ws]+)>( *(?<args>[^,)]+)(?:, *(?<args>[^,)]+))*)

这里最后一个子模式是:

( *(?<args>[^,)]+)(?:, *(?<args>[^,)]+))*)

RegEx Demo 2