Regex查找前两个字符串实例之间的电子邮件地址

Question

我有一连串电子邮件的原始文本。

For all inquiries please reach out
From: [e-mail] At: 01/27/21 23:29:28To: CompanyA
Cc: [e-mail], [e-mail] Subject: this is the subject line
From: CompanyB(company) <[e-mail]>
Sent: Wednesday, January 27, 2021 12:51 PM
From: [e-mail] At: 01/27/21 23:29:28To: CompanyA
Cc: [e-mail], [e-mail] Subject: tect

通过Regex，我需要从捕获第一个单词之间的电子邮件地址第一个主题． 在上面的匹配应该是:
[e-mail]
[e-mail]
[e-mail]

我有( n) {0,1} (( w。)@ ( w + -。))获取电子邮件地址。我将通过Python Regex Lib进行匹配。

Answer 1

一个选择是使用两个模式。

首先查找从From:到Subject:第一次出现的所有匹配

(?s)bFrom:.*?bSubject:

然后对于所有这些匹配，获得电子邮件地址类似模式，而不匹配<和>

[^<>s@]+@[^@s<>]+

例子

import re
s = ("For all inquiries please reach outn"
"From: [e-mail] At: 01/27/21 23:29:28To: CompanyAn"
"Cc: [e-mail], [e-mail] Subject: this is the subject linen"
"From: CompanyB(company) <[e-mail]>n"
"Sent: Wednesday, January 27, 2021 12:51 PMn"
"From: [e-mail] At: 01/27/21 23:29:28To: CompanyAn"
"Cc: [e-mail], [e-mail] Subject: tect")
for match in re.findall(r"(?s)bFrom:.*?bSubject:", s):
print(re.findall(r"[^<>s@]+@[^@s<>]+", match))

输出

['[e-mail]', '[e-mail],', '[e-mail]']
['[e-mail]', '[e-mail]', '[e-mail],', '[e-mail]']

---

如果您不想再次出现From:或Subject，您可以使用负向前看检查该行是否包含任何字符串。

^From:.*(?:r?n(?!From|.*bSubject:).*)*r?n.*bSubject:

Regex演示

例子

for match in re.findall(r"(?m)^From:.*(?:r?n(?!From|.*bSubject:).*)*r?n.*bSubject:", s):
print(re.findall(r"[^<>s@]+@[^@s<>]+", match))

输出

['[e-mail]', '[e-mail],', '[e-mail]']
['[e-mail]', '[e-mail],', '[e-mail]']