如何为updateview制作表单html

Question

我正在用我的html文件制作我自己的CreateView和UpdateView表单，因为我不想像这样显示表单{{form.as_p}}。

forms.py

from django import forms
from .models import Post
class PostCreationForm(forms.ModelForm):
class Meta:
model = Post
fields = ('title', 'cover', 'text',)
widgets = {
'title': forms.TextInput(attrs={'class': 'title'}),
'cover': forms.FileInput(attrs={'class': 'image'}),
'text': forms.TextInput(attrs={'class': 'text'})
}
class PostDeleteForm(forms.ModelForm):
class Meta:
model = Post
fields = ('__all__')

views.py

from django.shortcuts import reverse
from django.http import HttpResponseRedirect
from django.views import generic
from .models import Post
from .forms import PostCreationForm, PostDeleteForm
class PostListView(generic.ListView):
model = Post
context_object_view = 'post_list'
template_name = 'forum/post_list.html'

class PostDetailView(generic.DetailView):
model = Post
context_object_view = 'post'
template_name = 'forum/post_detail.html'
class PostCreateView(generic.CreateView):
model = Post
form_class = PostCreationForm
template_name = 'forum/post_create.html'
def form_valid(self, form):
if form.is_valid():
response = form.save(commit = False)
response.author = self.request.user
response.save()
return HttpResponseRedirect(reverse('post_detail', args=[str(response.id)]))

class PostUpdateView(generic.UpdateView):
model = Post
context_object_view = 'post'
form_class = PostCreationForm
template_name = 'forum/post_edit.html'
def get_post(self, pk):
return get_object_or_404(Post, pk=pk)
def form_valid(self, form):
if form.is_valid():
response = form.save(commit = False)
response.save()
return HttpResponseRedirect(reverse('post_detail', args=[str(response.id)]))

class PostDeleteView(generic.DeleteView):
model = Post
context_object_view = 'post'
form_class = PostDeleteForm
template_name = 'forum/post_delete.html'
success_url = '/'
def get_post(self, pk):
return get_object_or_404(Post, pk=pk)

post_create.html

{% extends '_base.html' %}
{% block css %}
{% load static %}
<link rel="stylesheet" href="{% static 'css/post_create.css' %}">
{% endblock css %}
{% block title %}Questions{% endblock title %}
{% block content %}
<h1 class="m-title">New Post</h1>
<div class="form">
<form action="" method="post" enctype="multipart/form-data" id='postform'>
{% csrf_token %}
<p class="n-title"><label for="id_title">Title: </label></p>
<input id="id_title" type="text" name="title" class="title" maxlength="40" required>
<p class="n-image"><label for="id_cover">Image: </label></p>
<input id="id_cover" type="file" name="cover" class="image" required>
<p class="n-text"><label for="id_text">Text: </label></p>
<textarea id="id_text" placeholder="Enter your text here" name="text" class="text" form='postform' required></textarea>
<button class="btn btn-success" id="button" type="submit">Submit</button>
</form>
</div>
{% endblock content %}

我也想为UpdateView做，但我不知道如何使输入字段显示帖子的当前值(标题，文本)。html文件与CreateView相同。我如何使输入显示正在修改的帖子的当前值?

Answer 1

您可能不想为表单手动编写html。

如果必须，可以传递如下值:

<input id="id_title" type="text" name="title" class="title" maxlength="40" value="{{ form.title.value }}" required>

最好是使用django渲染字段，这样你的表单字段属性，如maxlength和required匹配你的表单类规范。例如，这将为标题字段创建输入:

{{形式。标题}}

如果你想在样式上更灵活，请查看crisp -forms或我的首选floppyforms