如果我不将按钮拖动到我想拖动的位置，它如何转到第一个位置？

Question

输入图像描述这里我有9个按钮。三个在上面，三个在下面。所有3个按钮都在右侧。上面按钮上的反义词写在右边的按钮上。我想把这些反义词的按钮放在底部的按钮上。底部的按钮是有颜色的，它们的文本与右边的按钮相同，但它们的文本是不可见的，因为它与按钮的颜色相同。所以底部的按钮看起来像一个彩色的盒子。这就是我现在想做的;例如，button 1 = cold, button7 = hot。我想把这个按钮7放在按钮1下面的按钮4上，但是如果我想把它放在按钮5上，我想让它回到原来的位置。在我编写的代码中，只要我按下button7，它就会直接转到button4，我无法尝试其他按钮。我怎样才能尝试其他按钮，并将它们返回到Visual studio表单应用程序的第一个位置?

enter code here
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace materyalll
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
startlocation = new Point(button7.Left, button7.Top);
startlocation2 = new Point(button8.Left, button8.Top);
startlocation3 = new Point(button9.Left, button9.Top);
}
Point location, location2, location3, startlocation, startlocation2, startlocation3;

private void button7_MouseDown(object sender, MouseEventArgs e)
{
location = e.Location;
}
private void button7_MouseMove(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
button7.Left += e.X - (location.X);
button7.Top += e.Y - (location.Y);
}
}
private void button7_MouseUp(object sender, MouseEventArgs e)
{
if (button7.Text == button4.Text)
button7.Location = button4.Location;
else if (button7.Text != button5.Text)
button7.Location = startlocation;
else if (button7.Text != button6.Text)
button7.Location = startlocation;
}
private void button8_MouseDown(object sender, MouseEventArgs e)
{
location2 = e.Location;
}
private void button8_MouseMove(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
button8.Left += e.X - (location2.X);
button8.Top += e.Y - (location2.Y);
}
}       
private void button8_MouseUp(object sender, MouseEventArgs e)
{
if (button8.Text == button5.Text)
button8.Location = button5.Location;
else if (button8.Text != button4.Text)
button8.Location = startlocation2;
else if (button8.Text != button6.Text)
button8.Location = startlocation2;
}
private void button9_MouseDown(object sender, MouseEventArgs e)
{
location3 = e.Location;
}
private void button9_MouseMove(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
button9.Left += e.X - (location3.X);
button9.Top += e.Y - (location3.Y);
}
}
private void button9_MouseUp(object sender, MouseEventArgs e)
{

if (button9.Text == button6.Text)
button9.Location = button6.Location;
else if (button9.Text != button4.Text)
button9.Location = startlocation3;
else if (button9.Text != button5.Text)
button9.Location = startlocation3;
}
}
}

Answer 1

将按钮的原始位置存储在按钮本身的.Tag属性中。当用户松开鼠标时，查看正确目标按钮的矩形是否与当前按钮相交。如果没有，则返回到标签中的存储位置;

下面是button7:

public Form1()
{
InitializeComponent();
button7.Tag = button7.Location;
button8.Tag = button8.Location;
button9.Tag = button9.Location;
}
private void button7_MouseUp(object sender, MouseEventArgs e)
{
if (button7.Bounds.IntersectsWith(button4.Bounds)) {
button7.Location = button4.Location;
}
else
{
button7.Location = (Point)button7.Tag;
}
}

其他两个按钮的代码将非常相似。

Answer 2

试试这样:

Dictionary<string, Point> originalPoints = new Dictionary<string, Point>();
originalPoints.Add(nameof(button1), new Point(button1.Left, button1.Top));
// repeat this for all buttons
void SetToOriginalPosition(Button button)
{
Point p = originalPoints[nameof(button)];
button.Left = p.X;
button.Top = p.Y;
}