如何检查各种数字范围是否在一维对象数组中表示?

Question

我正在尝试检查从青少年到百岁老人的所有年龄组是否在数组中表示。

我的逻辑路径是:

• 创建一个数组，其中包含预定义的以十年为基础的年龄括号[1, 2, 3, ... , 10]
• 隔离对象样本数组中每个元素的年龄值
• 将这些年龄除以10得到年龄落在
的哪个年代
• parseInt的数字得到一个整数，并把结果数字在新的数组
• 将该数组与最初创建的预定义年龄括号数组进行比较。

预期输出是true，但我却得到false。

我面临的另一个逻辑问题是，样本数组中最老的年龄，128，在分割/解析后减少到12，而最好检查int是否为> 10，而不是具体的10。

下面的代码:

const devAges = list.map((list) => {
return list.age
})
const devAgesDiv = devAges.map(i => i / 10);
for(i = 0; i < devAgesDiv.length; i++){
devAgesDiv[i] = parseInt(devAgesDiv[i]);
}
function allAges(list) {
const ageBrackets = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
return ageBrackets.every((ageBracket) =>
list.some((listItem) => listItem.ageBracket === ageBracket)
);
}
console.log(allAges(list)); // output false;

示例数组如下:

var list = [
{ firstName: 'Harry', lastName: 'K.', country: 'Brazil', continent: 'Americas', age: 19, language: 'Python' },
{ firstName: 'Kseniya', lastName: 'T.', country: 'Belarus', continent: 'Europe', age: 29, language: 'JavaScript' },
{ firstName: 'Jing', lastName: 'X.', country: 'China', continent: 'Asia', age: 39, language: 'Ruby' },
{ firstName: 'Noa', lastName: 'A.', country: 'Israel', continent: 'Asia', age: 40, language: 'Ruby' },
{ firstName: 'Andrei', lastName: 'E.', country: 'Romania', continent: 'Europe', age: 59, language: 'C' },
{ firstName: 'Maria', lastName: 'S.', country: 'Peru', continent: 'Americas', age: 60, language: 'C' },
{ firstName: 'Lukas', lastName: 'X.', country: 'Croatia', continent: 'Europe', age: 75, language: 'Python' },
{ firstName: 'Chloe', lastName: 'K.', country: 'Guernsey', continent: 'Europe', age: 88, language: 'Ruby' },
{ firstName: 'Viktoria', lastName: 'W.', country: 'Bulgaria', continent: 'Europe', age: 98, language: 'PHP' },
{ firstName: 'Piotr', lastName: 'B.', country: 'Poland', continent: 'Europe', age: 128, language: 'JavaScript' }
];

Answer 1

您可以进行两次更新以获得所需的结果:

1. devAgesDiv-检查列表age是否大于100，返回10，否则除以10;您可以parseInt该测试的结果

2. 您可以在allAges中使用includes来检查everyageBracket是否表示

见下文:

const list = [
{ firstName: 'Harry', lastName: 'K.', country: 'Brazil', continent: 'Americas', age: 19, language: 'Python' },
{ firstName: 'Kseniya', lastName: 'T.', country: 'Belarus', continent: 'Europe', age: 29, language: 'JavaScript' },
{ firstName: 'Jing', lastName: 'X.', country: 'China', continent: 'Asia', age: 39, language: 'Ruby' },
{ firstName: 'Noa', lastName: 'A.', country: 'Israel', continent: 'Asia', age: 40, language: 'Ruby' },
{ firstName: 'Andrei', lastName: 'E.', country: 'Romania', continent: 'Europe', age: 59, language: 'C' },
{ firstName: 'Maria', lastName: 'S.', country: 'Peru', continent: 'Americas', age: 60, language: 'C' },
{ firstName: 'Lukas', lastName: 'X.', country: 'Croatia', continent: 'Europe', age: 75, language: 'Python' },
{ firstName: 'Chloe', lastName: 'K.', country: 'Guernsey', continent: 'Europe', age: 88, language: 'Ruby' },
{ firstName: 'Viktoria', lastName: 'W.', country: 'Bulgaria', continent: 'Europe', age: 98, language: 'PHP' },
{ firstName: 'Piotr', lastName: 'B.', country: 'Poland', continent: 'Europe', age: 128, language: 'JavaScript' }
];
const devAgesDiv = list.map(item => parseInt(item.age > 100 ? 10 : item.age / 10));
const ageBrackets = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
function allAges(list) {
return ageBrackets.every(ageBracket => list.includes(ageBracket));
}
console.log(allAges(devAgesDiv)); // true