读取和打印数据-协作

Question

请帮助我尝试打印结果，当我运行代码时没有打印任何内容。

#read the tweets stored in the file
tweets_data_path='tweet.txt'
tweets_data=[]
tweets_file=open(tweets_data_path,"r")
#read in tweets and store on list
for line in tweets_file:
tweet=json.loads(line)
tweets_data.append(tweet)
tweets_file.close() 
print(tweets_data[0])

我试图更改最后一行的缩进，但我收到以下错误

#read the tweets stored in the file
tweets_data_path='tweet.txt'
tweets_data=[]
tweets_file=open(tweets_data_path,"r")
#read in tweets and store on list
for line in tweets_file:
tweet=json.loads(line)
tweets_data.append(tweet)
tweets_file.close() 
print(tweets_data[0])

IndexError                                Traceback (most recent call last)
<ipython-input-48-f5407f1436ea> in <module>()
8   tweets_data.append(tweet)
9   tweets_file.close()
---> 10 print(tweets_data[0])
IndexError: list index out of range

请建议

Answer 1

如果文件为空，则没有要打印的内容。以下是我的建议，以避免由于空文件而导致的异常:

# read the tweets stored in the file
tweets_data_path = 'tweet.txt'
tweets_data = []
tweets_file = open(tweets_data_path, "r")
# read in tweets and store on list
for line in tweets_file:
tweet = json.loads(line)
tweets_data.append(tweet)
tweets_file.close()
if len(tweets_data) > 0:
print(tweets_data[0])