给来自两个不同文件的字典赋值

Question

我有一个像这样的bam.txt文件:

exomesinglesample_out/bam/pfg001G.GRCh38DH.target.bam
exomesinglesample_out/bam/pfg002G.GRCh38DH.target.bam
exomesinglesample_out/bam/pfg014G.GRCh38DH.target.bam

另一个文件bai.txt:

exomesinglesample_out/bam/pfg001G.GRCh38DH.target.bai
exomesinglesample_out/bam/pfg002G.GRCh38DH.target.bai
exomesinglesample_out/bam/pfg014G.GRCh38DH.target.bai

我想创建一个字典列表，它的键总是这样的:

keys = ['bam','bam_index']
d = dict.fromkeys(keys)
l = [d for x in range(3)]
print(l)
[{'bam': None, 'bam_index': None}, {'bam': None, 'bam_index': None}, {'bam': None, 'bam_index': None}]

字典应该是这样的，而不是有None值:

[{'bam': 'exomesinglesample_out/bam/pfg001G.GRCh38DH.target.bam', 'bam_index': 'exomesinglesample_out/bam/pfg001G.GRCh38DH.target.bai'}, {'bam': 'exomesinglesample_out/bam/pfg002G.GRCh38DH.target.bam', 'bam_index': 'exomesinglesample_out/bam/pfg002G.GRCh38DH.target.bai'}, {'bam': 'exomesinglesample_out/bam/pfg014G.GRCh38DH.target.bam', 'bam_index': 'exomesinglesample_out/bam/pfg014G.GRCh38DH.target.bai'}]

换句话说，字典列表中第一个字典的第一个值必须有bam.txt的第一行，列表中第一个字典的第二个值必须有bai.txt的第一行，直到两个文件的最后一行结束。

我知道dict值不能被索引，因为字典在python中是无序的数据类型，所以也许这需要用tuplesgenerators或list来解决。

Answer 1

可以使用zip()逐行遍历这两个文件，并将字典准备为:

keys = ['bam','bam_index']
l = []
with open('bam.txt', 'r') as f1, open('bai.txt', 'r') as f2:
for lf1, lf2 in zip(f1, f2):
d = {keys[0] : lf1.strip(), keys[1] : lf2.strip()}
l.append(d)
print(l)

输出:

[{'bam': 'exomesinglesample_out/bam/pfg001G.GRCh38DH.target.bam', 'bam_index': 'exomesinglesample_out/bam/pfg001G.GRCh38DH.target.bai'}, {'bam': 'exomesinglesample_out/bam/pfg002G.GRCh38DH.target.bam', 'bam_index': 'exomesinglesample_out/bam/pfg002G.GRCh38DH.target.bai'}, {'bam': 'exomesinglesample_out/bam/pfg014G.GRCh38DH.target.bam', 'bam_index': 'exomesinglesample_out/bam/pfg014G.GRCh38DH.target.bai'}]