Timeit 模块正在拒绝 print( "n" ) 语句

Question

我正在尝试运行以下代码示例

from timeit import timeit as t 
setup = '''
import time
from multiprocessing import Pool
def square(x):
square = x * x
time.sleep(1)
return square
'''
case01 = '''
def caso01(): 
print("nPART 1")

starttime = time.time()
pool = Pool(4)
pool.map(square, range(0, 5))
pool.close()
endtime1 = time.time()
print(f"Time taken {endtime1-starttime} seconds")
return None
'''
def main():
print( t(setup=setup,stmt=case01,number=100) )
return None
main()

和我总是得到相同的错误:

File "/usr/lib/python3.8/timeit.py", line 233, in timeit
return Timer(stmt, setup, timer, globals).timeit(number)
File "/usr/lib/python3.8/timeit.py", line 122, in __init__
compile(stmtprefix + stmt, dummy_src_name, "exec")
File "<timeit-src>", line 16
print("

我发现删除"n"从打印句子中，这个问题消失了。是否不能使用"n"与Timeit模块?我错过了什么?

感谢PS:在linux机器上使用Python 3

Answer 1

您需要添加一个前导反斜杠()来转义n，因为它在运行时被解码。

case01 = '''
def caso01(): 
print("\nPART 1")

starttime = time.time()
pool = Pool(4)
pool.map(square, range(0, 5))
pool.close()
endtime1 = time.time()
print(f"Time taken {endtime1-starttime} seconds")
return None
'''