Discord.py按钮响应交互在3分钟后失败

Question

如果3分钟内没有人点击该按钮，则该按钮不会响应。我看到它是超时的东西，但我不知道该放在哪里。

我的代码：

#Tickets
class Menu(discord.ui.View):
def __init__(self):
super().__init__()
self.value = None
@discord.ui.button(label="📥 Ticket", style=discord.ButtonStyle.grey)
async def menu1(self, interaction: discord.Interaction, button: discord.ui.Button):
with open("open_channels_user_id.json", "r") as f:
data = json.load(f)
user_id = data["user_id"]
if user_id != interaction.user.id:
admin_role = discord.utils.get(interaction.guild.roles, name="hulpje")
category = discord.utils.get(interaction.guild.categories, name='Ticket')
overwrites = {interaction.guild.default_role: discord.PermissionOverwrite(read_messages=False),
interaction.guild.me: discord.PermissionOverwrite(read_messages=True),
interaction.user: discord.PermissionOverwrite(read_messages=True),
admin_role: discord.PermissionOverwrite(read_messages=True)}
new_ticket = await interaction.guild.create_text_channel(f'Ticket- {interaction.user.name}', category=category, overwrites=overwrites)
channel = client.get_channel(new_ticket.id)
embed = discord.Embed(title=f'Ticket- {interaction.user.name}', description="Goed dat je een ticket opent. n Stuur alvast wat informatie zodat het makkelijker is voor het staff team.", color=0x004BFF)
await channel.send(embed=embed)
await interaction.response.send_message(f"Ticket is geopen met de naam: Ticket- {interaction.user.name}")
data['user_id'] = interaction.user.id
with open("open_channels_user_id.json", "w") as f:
json.dump(data, f)
time.sleep(3)
await interaction.channel.purge(limit=1)
else:
await interaction.channel.send("Je hebt al een ticket openstaan.")
time.sleep(5)
await interaction.channel.purge(limit=1)
async def menu(ctx):
view = Menu()
embed = discord.Embed(title="Ticket", description="Vragen, klachten of iets anders maak hier je Ticket aan en wordt zo snel mogelijk geholpen!", color=0x004BFF)
await ctx.send(embed=embed, view=view)

我不知道该怎么办。请帮忙！

Answer 1

您可以这样设置超时值：

class Menu(discord.ui.View):
def __init__(self):
super().__init__(timeout=180) # Timeout value in seconds
self.value = None

如果将其设置为None，则在重新启动机器人程序之前，它永远不会超时。
如果希望视图在机器人程序重新启动之间保持不变，请参阅此处的示例：https://github.com/Rapptz/discord.py/blob/master/examples/views/persistent.py