矩阵查找大于和小于变量的数据

Question

我的疑问是，我找不到一种方法来让它向我显示矩阵中大于和小于变量' mediatot ';的值。谢谢你的帮助

import numpy as np
ñ=0
fil = int (2)#Sucursal
col = int (3)#Dia
matriz=[]
for i in range (fil):
matriz.append([])
for j in range (col):
if j == 0:
p = str("Lunes")
j+1
if j == 1:
p = str("Martes")
j+1
if j == 2:
p = str("Miercoles")
j+1
if j == 3:
p = str("Jueves")
j+1
if j == 4:
p = str("Viernes")
j+1
if j == 5:
p = str("Sabado")
j+1
if j == 6:
p = str("Domingo")
j+1
valor = int (input("Sucursal {}, dia {} : ".format(i+1,p)))
matriz [i].append(valor)
def Mostrar():
print()
for fila in matriz:
print("t[",end="")
for elemento in fila:
print("",(elemento),"",end="")
print("]")
print()
o=(np.apply_along_axis(sum, 0, matriz))#columnas
medcol = o.mean()  
print ("La media de la semana es:",medcol)
Mostrar()
p=(np.apply_along_axis(sum, 1, matriz))#fila
#medfil = p.mean()  
print ("La media de cada sede es:",(p/col))
print(type(matriz))
dr= np.array(matriz)
print(type(dr))
mediatot = dr.mean()  
print("La media de la empresa es:",mediatot)

Answer 1

可以这样做:

boolMatriz = (matriz > mediatot)

给出一个布尔数组，当值大于mediatot时，该数组指示True。由于矩阵是一个列表，它需要被转换成np。数组使用布尔数组:

np.array(matriz)[boolMatriz]