如何在python的列表中获取字典中的值，并进一步从中索引值

Question

我有一个挑战问题需要解决，这是数据的样子，

data = [{'Clay':[x for x in range(2, 3)]}, 
{'George':[x for x in range(7)]}, 
{'Buddy':[x for x in range(5, 8)]}, 
{'Mark':[x for x in range(7, 11)]}, 
{'John':[x for x in range(1, 10)]}]

挑战问题是在数据中找到一个值，比如"Buddy"并进一步索引一个数字/值比如6，这是我到目前为止想到的但我在这里卡住了-

data = [{'Clay':[x for x in range(2, 3)]}, 
{'George':[x for x in range(7)]}, 
{'Buddy':[x for x in range(5, 8)]}, 
{'Mark':[x for x in range(7, 11)]}, 
{'John':[x for x in range(1, 10)]}]
def find_usr(usr, val):
if usr in data:
print("True")
else:
print("False")
find_usr(usr="Buddy", val=6)

它返回False我不确定这里出了什么问题，我在一个主题上做了一些搜索，但找不到可能的解决方案。
欢迎任何进一步的调试细节!

Answer 1

如果我理解你问的是正确的，我希望这段代码可以帮助:

def find_usr(usr, val):
for dictionary in data:
# Checking each dictionary in the list
if usr in dictionary.keys():
# Only if the user in the current dictionary
if val in dictionary[usr]:
# If the value in the list of the user
return True
# If the value is not in the list of the user
break  # We can stop the loop becuase we have found the user
return False

顺便说一下，如果您使用的是一个只有一个键和一个值的字典列表，那么使用字典而不是列表会更好:

data = {'Clay':[x for x in range(2, 3)], 
'George':[x for x in range(7)], 
'Buddy':[x for x in range(5, 8)], 
'Mark':[x for x in range(7, 11)], 
'John':[x for x in range(1, 10)]}

所以代码会更有效率:

def find_usr(usr, val):
if usr in data.keys():
# Only if the user in the current dictionary
if val in data[usr]:
# If the value in the list of the user
return True
# If the value is not in the list of the user
break  # We can stop the loop becuase we have found the user
return False