根据week_of_month和day_of_week标准构造日期

Question

我不确定如何去构建datetime对象给定year,month,week_of_month和day_of_week。有线索吗?使用这个，我试图实现以下目标:

From(start_month, start_year)to(end_month, end_year)findmonthly日期由week_of_month和day_of_week参数指定。这里是1 <= week_of_month <= 5和1 <= day_of_week <= 7。现在,

1. 每个月可能没有5周(例如;非闰年二月)
2. 第1周和第5周可能没有7天。

在这种情况下，基于布尔值is_to_next_day，如果True则指定下一个日历日，如果False则跳过它。

示例输入/输出:

1. 输入参数:start_month=1 start_year=2020, end_month=12, end_year=2020, week_of_month=5, day_of_week=3, is_to_next_day=True
   期望输出:[datetime(2020, 1, 29), datetime(2020, 2, 26), datetime(2020, 3, 25), datetime(2020, 4, 29), datetime(2020, 5, 27), datetime(2020, 7, 1), datetime(2020, 7, 29), datetime(2020, 8, 26), datetime(2020, 9, 30), datetime(2020, 10, 28), datetime(2020, 11, 25), datetime(2020, 12, 30)]
2. 输入参数:start_month=1 start_year=2020, end_month=12, end_year=2020, week_of_month=5, day_of_week=3, is_to_next_day=False
   期望输出:[datetime(2020, 1, 29), datetime(2020, 2, 26), datetime(2020, 3, 25), datetime(2020, 4, 29), datetime(2020, 5, 27), datetime(2020, 7, 29), datetime(2020, 8, 26), datetime(2020, 9, 30), datetime(2020, 10, 28), datetime(2020, 11, 25), datetime(2020, 12, 30)]

Answer 1

import calendar
from datetime import datetime
def get_date(year, month, week_of_month, day_of_week, is_to_next_day):
mnth = calendar.monthcalendar(year, month)
if (week_of_month > 1) and (week_of_month < 5):
day = mnth[week_of_month - 1][day_of_week - 1]
return datetime(year, month, day)
elif week_of_month == 1:
last_day_of_first_week = mnth[0][6]
if day_of_week <= last_day_of_first_week:
return datetime(year, month, day_of_week)
elif is_to_next_day:
return datetime(year, month, mnth[1][0])
else:
return None
else:
if (len(mnth) >= week_of_month):
day = mnth[week_of_month - 1][day_of_week - 1]
if(day==0) and is_to_next_day:
return datetime(year + int((month + 1)/12), (month + 1)%12, 1)
elif(day==0):
return None
else:
return datetime(year, month, day)
if (len(mnth) < week_of_month):
if is_to_next_day:
return datetime(year + int((month + 1)/12), (month + 1)%12, 1)
else:
return None
# First output
[get_date(yy, mm, 5, 3, True) for mm in range(1, 13) for yy in [2020]]
# Second output
[get_date(yy, mm, 5, 3, False) for mm in range(1, 13) for yy in [2020]] # Iterate again to drop None.