你能帮我用selenium点击Postcode Checker Search按钮吗?

Question

我正在尝试做一个教程，学习python中的Selenium，但我似乎无法让Selenium单击邮编搜索按钮。

我正在使用:

Python v3.9

Chrome v87

这是我正在练习的URL:

https://www.currys.co.uk/app/checkout

这是我当前的代码:

# Selenium Tutorial #1
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
import time
# Open Chromedriver
driver = webdriver.Chrome(r"C:UsersSte1337Desktopchromedriverchromedriver.exe")
# Open webpage
driver.get("https://www.currys.co.uk/gbuk/tv-and-home-entertainment/televisions/televisions/samsung-ue75tu7020kxxu-75-smart-4k-ultra-hd-hdr-led-tv-10213562-pdt.html")
# Click "Accept All Cookies" or ignore if no pop up
try:
element = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.ID, "onetrust-accept-btn-handler")))
element.click()
except Exception:
pass
# Wait 3 seconds
driver.implicitly_wait(3)
# Click "Add to Basket" or refresh page if out of stock
try:
element = WebDriverWait(driver, 1).until(EC.presence_of_element_located((By.XPATH, "email-desktop")))
time.sleep(5)
browser.refresh()
except:
button = driver.find_element_by_css_selector("button.Button__StyledButton-bvTPUF.hZIOeU.Button-jyKNMA.GZkwS")
driver.execute_script("arguments[0].click();", button)
# Wait 3 seconds
driver.implicitly_wait(3)
# Click "Continue to Basket"
button = driver.find_element_by_css_selector("button.Button__StyledButton-bvTPUF.hZIOeU.Button-jyKNMA.sc-fzpjYC.gJohPa")
driver.execute_script("arguments[0].click();", button)
# Wait 3 seconds
driver.implicitly_wait(3)
# Click "Go to checkout"
button = driver.find_element_by_xpath("//button[contains(@data-component, 'Button')][contains(@type, 'button')]")
driver.execute_script("arguments[0].click();", button)
# Type in postcode
search=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH, '//input[@aria-label="Postcode Checker"]')))
search.send_keys("NG229NU")
driver.implicitly_wait(1)
search.send_keys(Keys.RETURN)
# Click "Postcode finder"
postcode = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.NAME, "dcg-icon-search")))
postcode.click()

Answer 1

程序将search定义为邮政编码输入的explicit wait。search只会告诉你元素是否存在，但它不会选择它，所以你不能send_keys。

试试这段代码。您只需要等待元素存在，然后选择元素。只有这样你才能send_keys

# Type in postcode
WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH, '//input[@aria-label="Postcode Checker"]')))
search = driver.find_element_by_xpath('//input[@aria-label="Postcode Checker"]')
search.send_keys("NG229NU")
driver.implicitly_wait(1)
search.send_keys(Keys.RETURN)

Answer 2

如果你只想点击第一个选项，那么使用:

search = WebDriverWait(driver, 10).until(EC.element_to_be_clickable(
(By.XPATH, '//input[@aria-label="Postcode Checker"]')))
search.send_keys("NG229NU")
WebDriverWait(driver, 10).until(EC.element_to_be_clickable(
(By.CSS_SELECTOR, '[data-component = "SearchList"]')))
driver.switch_to_active_element().send_keys(Keys.RETURN)
driver.implicitly_wait(1)

这只是在第一个选项上按enter键。在这里，我们等待下拉并得到活动元素这是第一个选项，然后点击

选项