嘿,我有一个多对多关系在Knights
和Quests
两个表之间
我想写JPQL
查询,我从id 1的骑士获得1的id
任务,以后我会把它改为任务状态,但现在我想让它工作:
@Query("select k.quests from Knight k join k.quests q where k.id=1 and q.id=1")
Collection<Quest> findDoneStories();
它有点工作,因为它给我的任务从骑士id 1,但它给我所有的任务,而不是只有一个任务id 1。
@Entity
@Table(name = "knights")
public class Knight {
@Id
@Column(name = "id")
int id;
@Column
String name;
@Column(name = "status")
@Enumerated(EnumType.STRING)
private KnightEnum status;
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "knights_quests", joinColumns = @JoinColumn(name = "id_knights"),
inverseJoinColumns = @JoinColumn(name = "id_quest"))
List < Quest > stories;
}
@Entity
@Table(name = "quests")
public class Quest {
@Id
@Column(name = "id")
int id;
@Column
String name;
@Column(name = "description")
String description;
@Column(name = "status")
@Enumerated(EnumType.STRING)
QuestEnum status;
@Column(name = "story_points")
int storyPoints;
@ManyToMany(mappedBy = "stories", fetch = FetchType.EAGER)
List < Sprint > knights;
}
如果你只想得到一个Quest
,你的查询和方法应该是这样的:
@Query("SELECT DISTINCT q FROM Knight k JOIN k.stories q WHERE k.id = 1 AND q.id = 1")
Quest findDoneStories();
因为它是多对多的关系,你必须添加一个表knights_quests与列:knights_id和quests_id,你可以存储1和1,例如
你的实体将像这样:
@ManyToMany() @JoinTable(name = "knights_quests", joinColumns = @JoinColumn(name = "knighs_id", referencedColumnName = "id"), inverseJoinColumns = @JoinColumn(name = "quests_id",referencedColumnName = "name") )
当你可以用简单的连接执行查询后,JPQL会在后台处理它