根据一个数组的值打印另一个数组的值

Question

我试图根据布尔表打印出这些球场中每个球场可用的时间，但是，每个布尔值对应的时间保存在另一个表中。所以我的问题是如何根据另一个表的表打印一个表的值。下面是到目前为止的代码:

times = {
"times1": ["8","9","10","11","12","13","14","15","16","17"],
"times2": ["8","9","10","11","12","13","14","15","16","17"],
"times3": ["8","9","10","11","12","13","14","15","16","17"],
"times4": ["8","9","10","11","12","13","14","15","16","17"],
"times5": ["8","9","10","11","12","13","14","15","16","17"],
"times6": ["8","9","10","11","12","13","14","15","16","17"],
"times7": ["8","9","10","11","12","13","14","15","16","17"],
"times8": ["8","9","10","11","12","13","14","15","16","17"]
access = {
"access1": [True,False,False,True,True,False,False,False,True,True],
"access2": [False,False,True,True,False,False,False,False,True,True],
"access3": [False,False,False,True,True,False,True,False,True,False],
"access4": [True,True,False,True,True,True,False,False,True,True],
"access5": [True,False,False,True,True,False,False,False,True,False],
"access6": [True,False,False,True,True,False,True,True,False,True],
"access7": [True,True,True,True,True,False,False,False,True,True],
"access8": [True,False,True,True,False,False,False,False,True,True]
for i in access:
if access[i] == False:
print(times[i])

如果access为False，则应该打印该布尔值所在位置对应的时间

Answer 1

您只是遍历字典，而不是遍历每个字典条目中的值列表。因此，access[i]将是一个布尔值列表，而不是一个布尔值，并且与False的比较将总是失败。

你需要嵌套循环。

for a, t in zip(access.values(), times.values()):
for a1, t1 in zip(a, t):
if not a1:
print(t1, end=' ')
print()