获取python中XPATH表达式的空列表

Question

我在这个链接https://www.youtube.com/watch?v=EELySnTPeyw上观看了一个视频，这是代码(我已经更改了xpath，因为网站似乎已经更改)

import selenium.webdriver as webdriver
def get_results(search_term):
url = 'https://www.startpage.com'
browser = webdriver.Chrome(executable_path="D:\webdrivers\chromedriver.exe")
browser.get(url)
search_box = browser.find_element_by_id('q')
search_box.send_keys(search_term)
try:
links = browser.find_elements_by_xpath("//a[contains(@class, 'w-gl__result-title')]")
except:
links = browser.find_lemets_by_xpath("//h3//a")
print(links)
for link in links:
href = link.get_attribute('href')
print(href)
results.append(href)
browser.close()
get_results('cat')

对于打开浏览器并导航到搜索框和发送键的部分，代码工作得很好，但对于links返回一个空列表，尽管我在开发人员工具中手动搜索了xpath，它返回10个结果。

Answer 1

您需要添加键。输入你的搜索。你没在下一页。

search_box.send_keys(search_term+Keys.ENTER)

进口

from selenium.webdriver.common.keys import Keys

输出

https://en.wikipedia.org/wiki/Cat
https://www.cat.com/en_US.html
https://www.cat.com/
https://www.youtube.com/watch?v=cbP2N1BQdYc
https://icatcare.org/advice/thinking-of-getting-a-cat/
https://www.caterpillar.com/en/brands/cat.html
https://www.petfinder.com/cats/
https://www.catfootwear.com/US/en/home
https://www.aspca.org/pet-care/cat-care/general-cat-care
https://www.britannica.com/animal/cat