我正试图将List<String>
转换为TreeMap<Long, CustomClass>
,关键与列表项相同,但只是解析为Long
,该值只是对new CustomClass()
的调用。我如何使用lambda函数实现这一点?
List<String> list = List.of("1","2","3");
TreeMap<Long, CustomClass> resultMap = list.stream()
.collect(Collectors.toMap(i -> Long.parseLong(i), v -> new CustomClass()));
上面的代码出错了,下面的错误,
Required type: TreeMap<Long,CustomClass>
Provided: Map<Object,Object>
no instance(s) of type variable(s) K, U exist so that Map<K, U> conforms to TreeMap<Long, CustomClass>
例如:
final Map<Long, CustomClass> result = list.stream().collect(Collectors.toMap(Long::valueOf, ignore -> new CustomClass(), (x, y) -> y, TreeMap::new));
List<String> list = List.of("1","2","3");
HashMap<Long, CustomClass> map =
list.stream()
.collect(
Collectors.toMap(i->Long.parseLong(i),v->new CustomClass()));
TreeMap<Long, CustomClass> resultMap =new TreeMap(map);
没有测试,但应该给你一个想法。