如何在Django Rest框架中检索外部字段名

Question

我有两个模型一个用于用户，另一个用于用户的关联文件

Models.py

class IndividualUser(models.Model):
membership_id = models.CharField(primary_key=True, max_length=100, default=1)
profile_image = models.ImageField(blank=True, upload_to ="individual_member_profile/", null=True)
firstname = models.CharField(max_length=100)
lastname = models.CharField(max_length=100)
class MemberCatalogue(models.Model):
membership_id = models.ForeignKey(IndividualUser, default=None,on_delete=models.CASCADE, related_name="member_catalogue")
files = models.FileField(upload_to="individualmembercatalogue/")

目前我得到files的绝对路径。我需要一个用户上传的文件名，我试图获取"文件"字段，然后用"/"分隔它。但是我很难从membercatalog中获得文件字段。

我的序列化器现在是这样的:

class MemberCatalogueSerializer(serializers.ModelSerializer):
files = serializers.FileField()
class Meta:
model = MemberCatalogue
fields = ['id','membership_id', 'files']
class IndividualMembersSerializer(serializers.ModelSerializer):
member_catalogue = MemberCatalogueSerializer(many=True)
filename = serializers.SerializerMethodField('get_filename')
def get_filename(self, obj):
return obj.individualmember.files
class Meta:
model = IndividualMembers
fields = "__all__"

但是我不能得到想要的输出。预期输出类似于

{
"membership_id": "142369ca1b1484d8d9d6d87fdc8543db",
"member_catalogue": [
{
"id": 156,
"membership_id": "142369ca1b1484d8d9d6d87fdc8543db",
"files": "http://127.0.0.1:8000/individualmembercatalogue/some_file.pdf"
"filename" : "some_file.pdf"
}
],
"profile_image": null,
"firstname": "John",
"lastname": "Doe",
}

Answer 1

您在IndividualMembersSerializer中使用了错误的模型。我认为您正在尝试编辑文件名在错误序列化器中显示的方式，因为文件是MemberCatalogue上的字段，而不是IndividualUser上的字段。

我是这样做的:

class MemberCatalogueSerializer(serializers.ModelSerializer):
filename = serializers.SerializerMethodField()
def get_filename(self, obj):
return str(obj.files).split('/')[1]
class Meta:
model = MemberCatalogue
fields = ['id','membership_id', 'files', 'filename']
class IndividualMembersSerializer(serializers.ModelSerializer):
member_catalogue = MemberCatalogueSerializer(many=True)
class Meta:
model = IndividualUser
fields = "__all__"

Answer 2

class MemberCatalogueSerializer(serializers.ModelSerializer):
filename = serializers.SerializerMethodField()
class Meta:
model = MemberCatalogue
fields = ['membership_id', 'files','filename']
def get_filename(self, obj):
return obj.files.url.split('/')[-1]