有闪贷借多代币总是出错在硬帽

Question

我正在使用硬帽做AAVE闪贷，当我借一个代币时，是成功的，但借了>1令牌,总是错误。

* deploy on eth main -fork

flash-loans-test.js

const { ethers } = require("hardhat");
const hre = require("hardhat");
describe("AaveFlashLoans", function () {
it("Excute flashloans", async function () {
const contractAddress = "0xB53C1a33016B2DC2fF3653530bfF1848a515c8c5";
const flashLoansFactory = await ethers.getContractFactory("AaveFlashLoans");
const flashLoans = await flashLoansFactory.deploy(contractAddress);
await flashLoans.deployed();
const token = await ethers.getContractAt("IERC20", "0xC02aaA39b223FE8D0A0e5C4F27eAD9083C756Cc2"); //weth
const BALANCE_AMOUNT = ethers.utils.parseEther("2");
await hre.network.provider.request({
method: "hardhat_impersonateAccount",
params: ["0xf07704777d6bc182bf2c67fbda48913169b84983"],
});
const signer = await ethers.getSigner("0xf07704777d6bc182bf2c67fbda48913169b84983");
await token
.connect(signer)
.transfer(flashLoans.address, BALANCE_AMOUNT);
await flashLoans.myFlashLoanCall();
const balance = await token.balanceOf(flashLoans.address)
console.log(balance);
});
});

AaveFlashLoans.sol

pragma solidity ^0.8.0;
import {SafeMath} from "@openzeppelin/contracts/utils/math/SafeMath.sol";
import {IERC20} from "@openzeppelin/contracts/token/ERC20/IERC20.sol";
import {FlashLoanReceiverBase} from "./FlashLoanReceiverBase.sol";
import {ILendingPoolAddressesProvider} from "./ILendingPoolAddressesProvider.sol";
import "hardhat/console.sol";
contract AaveFlashLoans is FlashLoanReceiverBase {
using SafeMath for uint256;
constructor(ILendingPoolAddressesProvider _addressProvider)
FlashLoanReceiverBase(_addressProvider)
{}
function executeOperation(
address[] calldata assets,
uint256[] calldata amounts,
uint256[] calldata premiums,
address,
bytes calldata
) external override returns (bool) {
for (uint256 i = 0; i < assets.length; i++) {
uint256 amountOwing = amounts[i].add(premiums[i]);
IERC20(assets[i]).approve(address(LENDING_POOL), amountOwing);
console.log(amounts[i]);
console.log(premiums[i]);
}
return true;
}
function myFlashLoanCall() public {
address receiverAddress = address(this);
address[] memory assets = new address[](1);
assets[0] = address(0xC02aaA39b223FE8D0A0e5C4F27eAD9083C756Cc2); // weth
uint256[] memory amounts = new uint256[](1);
amounts[0] = 1 ether;
uint256[] memory modes = new uint256[](1);
modes[0] = 0;
address onBehalfOf = address(this);
bytes memory params = "";
uint16 referralCode = 0;
LENDING_POOL.flashLoan(
receiverAddress,
assets,
amounts,
modes,
onBehalfOf,
params,
referralCode
);
}
}

上面的代码是成功的成功image1成功image2

但是当我添加2个标记时，它会出错

AaveFlashLoans.sol

pragma solidity ^0.8.0;
import {SafeMath} from "@openzeppelin/contracts/utils/math/SafeMath.sol";
import {IERC20} from "@openzeppelin/contracts/token/ERC20/IERC20.sol";
import {FlashLoanReceiverBase} from "./FlashLoanReceiverBase.sol";
import {ILendingPoolAddressesProvider} from "./ILendingPoolAddressesProvider.sol";
import "hardhat/console.sol";
contract AaveFlashLoans is FlashLoanReceiverBase {
using SafeMath for uint256;
constructor(ILendingPoolAddressesProvider _addressProvider)
FlashLoanReceiverBase(_addressProvider)
{}
function executeOperation(
address[] calldata assets,
uint256[] calldata amounts,
uint256[] calldata premiums,
address,
bytes calldata
) external override returns (bool) {
for (uint256 i = 0; i < assets.length; i++) {
uint256 amountOwing = amounts[i].add(premiums[i]);
IERC20(assets[i]).approve(address(LENDING_POOL), amountOwing);
console.log(amounts[i]);
console.log(premiums[i]);
}
return true;
}
function myFlashLoanCall() public {
address receiverAddress = address(this);
address[] memory assets = new address[](2);
assets[0] = address(0xC02aaA39b223FE8D0A0e5C4F27eAD9083C756Cc2); // weth
assets[1] = address(0xdAC17F958D2ee523a2206206994597C13D831ec7); // usdt
uint256[] memory amounts = new uint256[](2);
amounts[0] = 1 ether;
amounts[1] = 1 ether;
uint256[] memory modes = new uint256[](2);
modes[0] = 0;
modes[1] = 0;
address onBehalfOf = address(this);
bytes memory params = "";
uint16 referralCode = 0;
LENDING_POOL.flashLoan(
receiverAddress,
assets,
amounts,
modes,
onBehalfOf,
params,
referralCode
);
}
}

上面的代码是错误的错误图片

请帮忙，谢谢很多很多很多很多…

Answer 1

由于USDT令牌有6个小数，通过将金额输入为1以太，这对应于金额:1000000000000 USDT。池中没有足够的可用流动性来借这么多钱，所以这就是tx回归的原因。如果你减少数量，那么它应该成功。