循环遍历一个嵌套字典以创建一个新字典

Question

我有一个像这样的嵌套字典:

d={'a1': {'b': ['x', 1]}, 'a2': {'b1': ['x1', 2]}}

预期结果:

[
{
"measurements": "XXXXX",
"tags": {
"MPC": b,
"host": a1
},
"time": "timexxxxx",
"fields": {
x: 1
}
},
{
"measurements": "XXXXX",
"tags": {
"MPC": b,
"host": a2
},
"time": "timexxxxx",
"fields": {
x: 1
}
}
]

这是我正在尝试的，但是它被覆盖了

for k,v in d.items():
metrics['measurements'] = "XXXXX"
if isinstance(v,dict):
for j,h in v.items():
metrics['tags'] = {'MPC':j,'host':k}
metrics['time'] = "timexxxxx"
for value in h:
metrics['fields'] = {j:h}

和我得到:

{'fields': {'b1': ['x1', 2]},
'measurements': 'XXXXX',
'tags': {'MPC': 'b1', 'host': 'a2'},
'time': 'timexxxxx'}

你能给我一些建议如何处理这件事吗?

感谢

Answer 1

见下文

import pprint
d = {'a1': {'b': ['x', 1]}, 'a2': {'b1': ['x1', 2]}}
data = []
for k, v in d.items():
entry = {"measurements": "XXXXX"}
entry['tags'] = {'MPC': list(v.keys())[0],"host": k}
entry["time"] =  "timexxxxx"
values= list(v.values())
entry["fields"] = {values[0][0]:values[0][1]}
data.append(entry)
pprint.pprint(data)

输出

[{'fields': {'x': 1},
'measurements': 'XXXXX',
'tags': {'MPC': 'b', 'host': 'a1'},
'time': 'timexxxxx'},
{'fields': {'x1': 2},
'measurements': 'XXXXX',
'tags': {'MPC': 'b1', 'host': 'a2'},
'time': 'timexxxxx'}]

Answer 2

以下代码可以帮助您:

d={'a1': {'b': ['x', 1]}, 'a2': {'b1': ['x1', 2]}}

def convert(dictionary):
return [
{
"measurements": "XXXXX",
"tags": {
"MPC": list(value.keys())[0],
"host": key
},
"time": "timexxxxx",
"fields": dict(value.values())
} for key, value in dictionary.items()
]

print(convert(d))

[{'measurements': 'XXXXX', 'tags': {'MPC': 'b', 'host': 'a1'}, 'time': 'timexxxxx', 'fields': {'x': 1}}, {'measurements': 'XXXXX', 'tags': {'MPC': 'b1', 'host': 'a2'}, 'time': 'timexxxxx', 'fields': {'x1': 2}}]

Answer 3

你可以这样做

#Empty List
li=[]
#Add Items in list
for i in range(2):
d = {}
d["measurment"] = "XXXXX"
d["tags"] = {1: "x"}
d["time"] = "timexxx"
d["field"] = {2: "y"}
li.append(d)
#Print list elements
for i in li:
for key, value in i.items():
print(key, ":", value)
print()