文件夹路径:D:Brianadrk_v1_0;这个文件夹有一个名为的文件filename'我想用命令提示符打开'filename'文件。
我试着这样做了,写了下面的
C:UsersAnshuman
C:UsersAnshuman> cd /d D:Brianadrk_v1_0
D:Brianadrk_v1_0>
但是当我试图打开'makefile'时,会发生这种情况:
Directory of D:Brianadrk_v1_0
03-10-2021 11:13 <DIR> .
03-10-2021 11:13 <DIR> ..
13-12-2002 22:16 <DIR> Const
13-12-2002 22:16 <DIR> Energy
13-12-2002 22:16 <DIR> Form
13-12-2002 22:16 <DIR> GMICPP
13-12-2002 22:16 <DIR> Group
13-12-2002 22:16 <DIR> Input
14-12-2002 04:13 1,046 i_data.txt
11-12-2002 03:50 3,294 makefile
13-12-2002 22:16 <DIR> Master
13-12-2002 22:16 <DIR> Output
14-12-2002 04:20 223 o_rmv.dat
14-12-2002 04:20 3,718 o_sdf.dat
14-12-2002 04:20 223 o_sum.dat
14-12-2002 04:20 151 o_vac.dat
13-12-2002 22:16 <DIR> PD
14-12-2002 06:16 2,394 readme.txt
13-12-2002 22:16 <DIR> SDF
13-12-2002 22:16 <DIR> Vector
7 File(s) 11,049 bytes
13 Dir(s) 579,931,025,408 bytes free
D:Brianadrk_v1_0>makefile
'makefile' is not recognized as an internal or external command,
operable program or batch file.
我已经尝试将环境变量中的路径更改为C: System 32。
看起来应该指定一个文本编辑器,例如:
notepad makefile