我怎么能用笑话来模拟打字界面呢

Question

我想模拟一个typescript接口，我该如何实现？当我得到人类的属性时，我想返回"Test"one_answers"ALIVE"。我在尝试编译下面给定的代码时遇到了困难。

错误

TS2345: Argument of type '() => void' is not assignable to parameter of type '() => Human'.   Type 'void' is not assignable to type 'Human'.

示例代码

enum STATUS
{
DEAD,
ALIVE
}

export interface Human {
name: string;
status: STATUS.ALIVE | STATUS.DEAD;
};

describe('Human', () => {
const mock = jest.fn<Human,[]>(() => {
name   : jest.fn(() => { return 'Test' });
status : jest.fn(() => { return STATUS.ALIVE });
});
it('should return properties',() => {
console.log(human.name);
console.log(human.status);
});
});

Answer 1

为name和status属性返回模拟函数，但它们是NOT函数类型。您应该为Human接口的这两个属性返回string和enum。

enum STATUS {
DEAD,
ALIVE,
}
export interface Human {
name: string;
status: STATUS.ALIVE | STATUS.DEAD;
}
describe('Human', () => {
const mock = jest.fn<Human, []>(() => {
return {
name: 'Test',
status: STATUS.ALIVE,
};
});
it('should return properties', () => {
const human = mock();
expect(human.name).toEqual('Test');
expect(human.status).toEqual(STATUS.ALIVE);
});
});