Regex删除包含图形或表引用的括号

Question

我想从包含表或图形引用的字符串中删除括号。括号中可以包含多个引用。这种模式在某种程度上是必然的。以下是一些例子：

text = [
"this is a figure ref (figure 7xe2x80x9377)",
"this is multiple refs (figures 6xe2x80x9328 and 6xe2x80x9329)",
"this is a table ref (table 6xe2x80x931)"
]

我使用以下正则表达式：

text = re.sub(r"(([w]sd(\[a-z]+[0-9])+))", " ", text)

Answer 1

您可以删除任何以table或figure:开头的括号

re.sub(r's*(s*(?:table|figure)[^()]*)', '', text)

请参阅regex演示详细信息：

• s*(s*-(两端包含零个或多个空格
• (?:table|figure)-table或figure字符串
• [^()]*-除(和)之外的零个或多个字符
• )-一个)字符

请参阅Python演示：

import re
text = [
"this is a figure ref (figure 7xe2x80x9377)",
"this is multiple refs (figures 6xe2x80x9328 and 6xe2x80x9329)",
"this is a table ref (table 6xe2x80x931)"
]
text = [re.sub(r's*(s*(?:table|figure)[^()]*)', '', t) for t in text]
print(text)
# => ['this is a figure ref', 'this is multiple refs', 'this is a table ref']