我正在使用laravel 5.5我有一个多选下拉列表。如果我不选择任何值，就会产生一个错误"内爆((：传递的参数无效">
<select multiple="multiple" name="language[]">
@foreach($language_data as $language)
<option value="{{$language->language_id}}">{{$language->language_name}}</option>
@endforeach
</select>
控制器
$language = $request->input('language');
$language = implode(',', $language);
DB::table('language')->insert(['language' => $language,]);
只需使用一个简单的if:
if($request->input('language') !== ''){
$language = $request->input('language');
$language = implode(',', $language);
DB::table('language')->insert(['language' => $language,]);
}
如果需要的话，如果没有像下面的那样选择语言，你可以在后端定义一种语言
$request->input('language') !== '' ? $language = $request->input('language') : $language = 'en_GB';
$language = implode(',', $language);
DB::table('language')->insert(['language' => $language,]);
试试这个，应该可以解决问题
$language = ''; //set default language here
if($request->input('language')) {
$language = $request->input('language');
$language = implode(',', $language);
}
DB::table('language')->insert(['language' => $language,]);
只需在内爆前执行一次检查。
$language = $request->input('language');
if (!empty($language)) {
$language = implode(',', $language);
} else {
$language = '';
}
DB::table('language')->insert(['language' => $language]);
$language = optional(collect($request->input('language')))->implode(',');
DB::table('language')->insert(['language' => $language]);
从$request值中生成一个集合，在事件中包装为可选"language"不是必需属性，内爆结果。