Mule 4:将SQL XML对象转换为JSON

Question

我正在获取SQLXML结果集，作为从数据库执行存储过程形状调用的MS SQL存储过程的输出。

SQLXML结果集看起来像：

<xmlcontent>
<field1>val1</field1>
<field2>val2</field2>
<field3>val3</filed3>
</xmlcontent>
<xmlcontent>
<field1>val1</field1>
<field2>val2</field2>
<field3>val3</filed3>
</xmlcontent>
<xmlcontent>
<field1>val1</field1>
<field2>val2</field2>
<field3>val3</filed3>
</xmlcontent>

然而，有效载荷有点奇怪，因为它包含长度为2033的XML输出，然后作为数组元素重复，直到有效载荷耗尽。只有有效载荷的变换形状输出显示：

{
"resultSet1": [
{
"XML_F52E2B61-18A1-11d1-B105-00805F49916B": "<xmlcontent><field1/><field2/><field3/>" --this content is of size 2033 max
},
{
"XML_F52E2B61-18A1-11d1-B105-00805F49916B": "</xmlcontent><xmlcontent><field1/><fiel" --this content is of size 2033 max
},
{
"XML_F52E2B61-18A1-11d1-B105-00805F49916B": "d2/><field3/><xmlcontent>"
}
]
}

我正在考虑使用另一个变换形状来附加"0"的值；XML_F52E2B61-18A1-11d11-B105-00805F49916B"；从resultset1数组，然后转换为JSON。在数据编织中有没有一种方法可以简化这种方法，以获得如下所示的最终JSON输出？

[
{
"field1": "val1",
"field2": "val2",
"field3": "val3"
},
{
"field1": "val1",
"field2": "val2",
"field3": "val3"
},
{
"field1": "val1",
"field2": "val2",
"field3": "val3"
}
]

Answer 1

输入：

{
"resultSet1": [
{
"XML_F52E2B61-18A1-11d1-B105-00805F49916B": "<xmlcontent><field1>val1</field1><field2>val2</field2><field3>val3</field3>" 
},
{
"XML_F52E2B61-18A1-11d1-B105-00805F49916B": "</xmlcontent><xmlcontent><field1>val1</field1><fiel" 
},
{
"XML_F52E2B61-18A1-11d1-B105-00805F49916B": "d2>val2</field2><field3>val3</field3></xmlcontent>"
}
]
}

脚本：

%dw 2.0
output application/json
var id='XML_F52E2B61-18A1-11d1-B105-00805F49916B'
var body=payload.resultSet1 map (
$[id]) reduce ((item, accumulator) -> accumulator ++ item)
---
read('<root>' ++ body ++ '</root>', "application/xml").root.*xmlcontent

输出：

[
{
"field1": "val1",
"field2": "val2",
"field3": "val3"
},
{
"field1": "val1",
"field2": "val2",
"field3": "val3"
}
]