我需要获取给定某个区域ID的所有子区域ID。在表areas
中,有一个引用areas
表本身的parent_id
字段。现在可以有多个级别,例如具有 id 的区域1
可以是具有 id2
的区域的父级,而具有 id 的区域2
可以是具有 id3
的区域的父级,依此类推。因此,当我调用此函数时,我需要某个区域 id 的所有后代。
SELECT id, get_all_children(id) as children from areas where id = 1;
结果应该是
| id | children |
| -------- | -------------- |
| 1 | {2,3} |
这是我到目前为止尝试过的
CREATE OR REPLACE FUNCTION get_all_children(ancestors INT[])
RETURNS INT[]
LANGUAGE plpgsql
AS
$$
DECLARE
childrenRet INT[];
BEGIN
SELECT
ARRAY_AGG(id::INT) INTO childrenRet
FROM areas
WHERE parent_id = ANY(ancestors);
IF childrenRet = '{}' THEN
RETURN childrenRet;
END IF;
RETURN ARRAY_CAT(get_all_children(childrenRet), childrenRet);
END;
$$;
SELECT id, get_all_children(id) as children from areas where id = 492;
但我得到的结果是
| id | children |
| -------- | -------------- |
| 492 | {3044} |
我尝试将直接孩子归还为
CREATE OR REPLACE FUNCTION get_all_children(ancestors INT[])
RETURNS INT[]
LANGUAGE plpgsql
AS
$$
DECLARE
childrenRet INT[];
BEGIN
SELECT
ARRAY_AGG(id::INT) INTO childrenRet
FROM areas
WHERE parent_id = ANY(ancestors);
RETURN childrenRet;
END;
$$;
SELECT id, get_all_children(id) as children from areas where id = 492;
我仍然得到相同的结果。
现在我试过了
SELECT ARRAY_AGG(id) FROM areas WHERE parent_id = 492;
这是我得到的结果
array_agg
------------------------------------------------------------------------------------
{3044,3075,923,1470,774,1466,1473,1468,1467,3043,1471,1469,922,1472,3076,1474,920}
我猜问题就在这里,但我不知道如何处理它。
SELECT
ARRAY_AGG(id::INT) INTO childrenRet
FROM areas
WHERE parent_id = ANY(ancestors);
在递归找到所有子项后,您可以简单地将array_agg
操作推迟到最后一个查询表达式,如下所示:
小提琴
-- Aggregate all of the recursively found descendants
WITH RECURSIVE cte01 (children, lev) AS (
SELECT a1.id, 0 FROM areas AS a1 WHERE a1.parent_id = 1 UNION ALL
SELECT a1.id, lev+1
FROM areas AS a1
JOIN cte01 AS c1
ON a1.parent_id = c1.children
)
SELECT array_agg(children ORDER BY lev, children) AS children FROM cte01
;
结果:
children |
---|
{2,3,492,774,920,922,923,1466,1467,1468,1469,1470,1471,1472,1473,1474,3043,3044,3075,3076} |