如果user_num2大于 8，则user_num2分配 5。打印"user_num2 is less than or equal to 8."

Question

任务：打印"；user_num1为负数"如果user_num1小于0。以换行符结束。如果user_num2大于8，则用5指定user_num2。否则，打印"；num2小于或等于8；。以换行符结束。

问题：我已经附上了我的代码，由于某种原因，当user_num2=8时，它不会输出输出图像中所示的print语句。我做错了什么？

尝试的代码：

user_num1 = int(input())
user_num2 = int(input())
if user_num1 < 0:    
print('user_num1 is negative.')
elif user_num2 <= 8:
print('user_num2 is less than or equal to 8.')
else:
user_num2 = 5
print('user_num2 is', user_num2)

Answer 1

每个用户都有自己的"如果"；声明。试试这个：

user_num1 = int(input())
user_num2 = int(input())
if user_num1 < 0:
print('user_num1 is negative.')
if user_num2 > 8:
user_num2 = 5
else:
print('user_num2 is less than or equal to 8.')
print('user_num2 is', user_num2)

Answer 2

这是我从文本中理解的内容：user_num1和user_num2测试是独立的，因此每个测试都有自己的"；如果"；陈述否则，当user_num1<0.

user_num1 = int(input())
user_num2 = int(input())
if user_num1 < 0:    
print('user_num1 is negative.')
if user_num2 <= 8:
print('user_num2 is less than or equal to 8.')
else:
user_num2 = 5
print('user_num2 is', user_num2)