将对象转换为按比例分配的数组

Question

我需要转换对象：

{
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
}

到阵列：

[{
key: "name",
propertyValue: "Test Name",
},
{
key: "middleName",
propertyValue: null,
},
{   
key: "university.isGraduated",
propertyValue: true,
},
{   
key: "university.speciality",
propertyValue: "Computer Science", 
},
{   
key: "university.country.code",
propertyValue: "PL"
}];

我写了算法，但它很假，我该如何改进它？重要的是，如果对象有嵌套对象，那么我需要通过点(例如university.contry:"value")写入嵌套对象

let arr = [];
Object.keys(parsedObj).map((key) => {
if (parsedObj[key] instanceof Object) {
Object.keys(parsedObj[key]).map((keyNested) => {
if (parsedObj[key][keyNested] instanceof Object) {
Object.keys(parsedObj[key][keyNested]).map((keyNestedNested) => {
arr.push({ 'key': key + '.' + keyNested + '.' + keyNestedNested, 'propertyValue': parsedObj[key][keyNested][keyNestedNested] })
})
} else {
arr.push({ 'key': key + '.' + keyNested, 'propertyValue': parsedObj[key][keyNested] })
}
})
} else {
arr.push({ 'key': key, 'propertyValue': parsedObj[key] })
}
});

感谢

Answer 1

递归函数实现。

我认为您的对象只包含字符串和作为值的对象。如果你有更多类型的数据类型作为你的值，你可能必须在这个函数的基础上进行开发。

const myObj = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
}
const myArr = [];
function convertObjectToArray(obj, keyPrepender) {
Object.entries(obj).forEach(([key, propertyValue]) => {
if (typeof propertyValue === "object" && propertyValue) {
const updatedKey = keyPrepender ? `${keyPrepender}.${key}` : key;
convertObjectToArray(propertyValue, updatedKey)
} else {
myArr.push({
key: keyPrepender ? `${keyPrepender}.${key}` : key,
propertyValue
})
}
})
}
convertObjectToArray(myObj);
console.log(myArr);

Answer 2

我可能会采用递归方法，并且可能会避免不必要的中间数组(尽管除非原始对象是巨大的，否则这无关紧要)。例如(见注释)：

function convert(obj, target = [], prefix = "") {
// Loop through the object keys
for (const key in obj) {
// Only handle "own" properties
if (Object.hasOwn(obj, key)) {
const value = obj[key];
// Get the full key for this property, including prefix
const fullKey = prefix ? prefix + "." + key : key;
if (value && typeof value === "object") {
// It's an object...
if (Array.isArray(value)) {
throw new Error(`Arrays are not valid`);
} else {
// ...recurse, providing the key as the prefix
convert(value, target, fullKey);
}
} else {
// Not an object, push it to the array
target.push({key: fullKey, propertyValue: value});
}
}
}
// Return the result
return target;
}

实例：

const original = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
};
function convert(obj, target = [], prefix = "") {
// Loop through the object keys
for (const key in obj) {
// Only handle "own" properties
if (Object.hasOwn(obj, key)) {
const value = obj[key];
// Get the full key for this property, including prefix
const fullKey = prefix ? prefix + "." + key : key;
if (value && typeof value === "object") {
// It's an object...
if (Array.isArray(value)) {
throw new Error(`Arrays are not valid`);
} else {
// ...recurse, providing the key as the prefix
convert(value, target, fullKey);
}
} else {
// Not an object, push it to the array
target.push({key: fullKey, propertyValue: value});
}
}
}
// Return the result
return target;
}
const result = convert(original, []);
console.log(result);

.as-console-wrapper {
max-height: 100% !important;
}

请注意，我假设数组条目的顺序并不重要。您所说的输出与JavaScript对象属性的标准顺序不一致(是的，它们现在有了顺序；不，我不建议依赖它)。我已经开始了，并不担心对象内的顺序。

Answer 3

这是我能做的最防弹的：D，不需要全局变量，你只需要它，我们可以随心所欲！

const test = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
};

function toPropertiesByPath(inputObj) {
let arr = [];
let initialObj = {};
const getKeys = (obj, parentK='') => {
initialObj = arr.length === 0 ? obj: initialObj;
const entries = Object.entries(obj);
for(let i=0; i<entries.length; i++) {
const key = entries[i][0];
const val = entries[i][1];
const isRootElement = initialObj.hasOwnProperty(key);
parentK = isRootElement ? key: parentK+'.'+key;
if(typeof val === 'object' && val!==null && !Array.isArray(val)){
getKeys(val, parentK);
} else {
arr.push({ key: parentK, property: val });
}
}
};
getKeys(inputObj);
return arr;
}
console.log(toPropertiesByPath(test));

Answer 4

我使用递归函数编写了一个小版本，另一个用于验证的版本是一个对象。

let values = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
}
function isObject(obj) {
return obj != null && obj.constructor.name === "Object"
}
function getValues(values) {
let arrValues = Object.keys(values).map(
v => {
return { key: v, value: isObject(values[v]) ? getValues(values[v]) : values[v] };
});
console.log(arrValues);
}
getValues(values);