如何查找布尔值

Question

x =[1,2,3,4,5,6]
y = [1,2,3,4,5]
if x == y:
print("Numbers found")
else:
print("Numbers not found")

我想打印列表y中不存在的数字。

Answer 1

最快的方法是在集合中转换并打印差异：

>>> print(set(x).difference(set(y)))
{6}

此代码打印x中存在但不存在于y中的编号

Answer 2

您可以这样做：

x = [1,2,3,4,5,6]
y = [1,2,3,4,5]
for i in x:
if i not in y:
print(i)

Answer 3

x =[1,2,3,4,5,6]
y = [1,2,3,4,5]
for i in x:
if i in y:
print(f"{i} found")
else:
print(f"{i} not found")

Answer 4

在我看来，这是最好的选择。

x =[1,2,3,4,5,6]
y = [1,2,3,4,5]
for number in x:
if number not in y:
print(f"{number} not found")

Answer 5

获取不匹配项：

def returnNotMatches(a, b):
return [[x for x in a if x not in b], [x for x in b if x not in a]]

或

new_list = list(set(list1).difference(list2))

到达十字路口：

list1 =[1,2,3,4,5,6]
list2 = [1,2,3,4,5]
list1_as_set = set(list1)
intersection = list1_as_set.intersection(list2)

输出：

{1, 2, 3, 4, 5}

你也可以把它转移到一个列表：

intersection_as_list = list(intersection)

或：

new_list = list(set(list1).intersection(list2))