未能使用curl将json发布到端点

  • 本文关键字:端点 json curl php curl
  • 更新时间 :
  • 英文 :


我正在尝试创建一个简单的api,该api将使用curl和php将json发布到端点。它给了我一个错误,它说不支持的媒体类型,我需要帮助看看它是什么,我可能做错了,这是代码

<?php
$data = array("saleAmount"=>"2000","cashBack"=>"800","posUser"=>"John","tenderType"=>"SWIPE","currency"=>"RTGS","transactionId"=>'0001');
$payload = json_encode($data);
echo $payload;
// prepare curl
$ch = curl_init('http://localhost:9111/api/requests');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLINFO_HEADER_OUT, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $payload);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(                                                                
'Content-Type: application/jsonp',                                                     
'Content-Length: ' . strlen($payload))                                                                       
);
// Submit the POST request
$result = curl_exec($ch);
echo json_encode($result);
// Close cURL session handle
curl_close($ch);
?>

问题是您的API期望的媒体类型与您在任务中提供的媒体类型不同。

https://developer.mozilla.org/en-US/docs/Web/HTTP/Status/415

确保您的API支持内容类型application/json

$url="";//path of api
$ch=curl_init($url);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json')
);
$data = array("saleAmount"=>"2000","cashBack"=>"800","posUser"=>"John","tenderType"=>"SWIPE","currency"=>"RTGS","transactionId"=>'0001');
$data=json_encode($data);
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch,CURLOPT_POST,true);
curl_setopt($ch,CURLOPT_POSTFIELDS,$data);
$response=curl_exec($ch); 
print_r($response);die;
curl_close($ch);
Append your url in $url and check this once.

最新更新