从数组中删除指定日期之前的对象javascript

Question

嗨，我已经到处找了，但无法完成

我想从阵列中删除过时的(直到昨天)对象

我的阵列看起来像这个

[{"apdate": "09-12-2020", "booked": "14:30"}, 
{"apdate": "11-12-2020", "booked": "19:30"}, 
{"apdate": "10-12-2020", "booked": "19:00"}, 
{"apdate": "17-12-2020", "booked": "14:30"}, 
{"apdate": "17-12-2020", "booked": "15:30"}, 
{"apdate": "17-12-2020", "booked": "19:00", "phone": "9898989898"}, 
{"apdate": "10-01-2021", "booked": "16:00"}, 
{"apdate": "29-01-2021", "booked": "18:30"}, 
{"apdate": "01-02-2021", "booked": "14:00", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{"apdate": "01-02-2021", "booked": "10:00", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{"apdate": "01-02-2021", "booked": "03:30", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}]

请引导我

Answer 1

我想从数组中删除过时的(最多yesterday)对象

老实说，你应该记住，永远不要改变你的数据

==>根据您的需要使用它即可

您可以使用.filter根据given_date筛选数据。

const data = [
{apdate: "09-12-2020", booked: "14:30"}, 
{apdate: "11-12-2020", booked: "19:30"}, 
{apdate: "10-12-2020", booked: "19:00"}, 
{apdate: "17-12-2020", booked: "14:30"}, 
{apdate: "17-12-2020", booked: "15:30"}, 
{apdate: "17-12-2020", booked: "19:00", phone: "9898989898"}, 
{apdate: "10-01-2021", booked: "16:00"}, 
{apdate: "29-01-2021", booked: "18:30"}, 
{apdate: "01-02-2021", booked: "14:00", name: "Anand", uuid: "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{apdate: "01-02-2021", booked: "10:00", name: "Anand", uuid: "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{apdate: "01-02-2022", booked: "03:30", name: "Anand", uuid: "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}
];

const convertStringToDate = (strDate) => {
const values = strDate.split("-");
return new Date(values[2], values[1] - 1, values[0]);
};
const filterDataByGivenDate = (data, givenDate) =>  data.filter(r => convertStringToDate(r.apdate) >= givenDate);

const today = new Date();
const yesterday = today.setDate(today.getDate() - 1);
console.log(filterDataByGivenDate(data, yesterday));

更优雅的方法是使用moment.js

const data = [
{apdate: "09-12-2020", booked: "14:30"}, 
{apdate: "11-12-2020", booked: "19:30"}, 
{apdate: "10-12-2020", booked: "19:00"}, 
{apdate: "17-12-2020", booked: "14:30"}, 
{apdate: "17-12-2020", booked: "15:30"}, 
{apdate: "17-12-2020", booked: "19:00", phone: "9898989898"}, 
{apdate: "10-01-2021", booked: "16:00"}, 
{apdate: "29-01-2021", booked: "18:30"}, 
{apdate: "01-02-2021", booked: "14:00", name: "Anand", uuid: "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{apdate: "01-02-2021", booked: "10:00", name: "Anand", uuid: "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{apdate: "01-02-2022", booked: "03:30", name: "Anand", uuid: "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}
];

const filterDataByGivenDate = (data, givenDate) => data.filter(r => moment(r.apdate, 'DD-MM-YYYY').isSameOrAfter(givenDate));
const yesterday = moment().subtract(1, 'days');
console.log(filterDataByGivenDate(data, yesterday));

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.29.1/moment.min.js"></script>

---

filter()方法创建一个新数组，其中所有元素由所提供的功能实现的测试。

Answer 2

您可以使用Lodash Filter&把它组合起来，moment.js就可以了。

const data = [
{"apdate": "09-12-2020", "booked": "14:30"}, 
{"apdate": "11-12-2020", "booked": "19:30"}, 
{"apdate": "10-12-2020", "booked": "19:00"}, 
{"apdate": "17-12-2020", "booked": "14:30"}, 
{"apdate": "17-12-2020", "booked": "15:30"}, 
{"apdate": "17-12-2020", "booked": "19:00", "phone": "9898989898"}, 
{"apdate": "10-01-2021", "booked": "16:00"}, 
{"apdate": "29-01-2021", "booked": "18:30"}, 
{"apdate": "01-02-2021", "booked": "14:00", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{"apdate": "01-02-2021", "booked": "10:00", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{"apdate": "01-02-2021", "booked": "03:30", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}
];
const filteredData = _.filter(data, item => {
const apdate = moment(item.apdate, 'DD-MM-YYYY');
const today = moment();
const difference = apdate.diff(today, 'days');

// You can modify the condition according to your requirements;
return difference >= 0;
});
console.log(filteredData)

Answer 3

过滤数组并保留所需的唯一数组。根据需要添加日期比较逻辑。

let a = [{"apdate": "09-12-2020", "booked": "14:30"}, 
{"apdate": "11-12-2020", "booked": "19:30"}, 
{"apdate": "10-12-2020", "booked": "19:00"}, 
{"apdate": "17-12-2020", "booked": "14:30"}, 
{"apdate": "17-12-2020", "booked": "15:30"}, 
{"apdate": "17-12-2020", "booked": "19:00", "phone": "9898989898"}, 
{"apdate": "10-01-2021", "booked": "16:00"}, 
{"apdate": "29-01-2021", "booked": "18:30"}, 
{"apdate": "01-02-2021", "booked": "14:00", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{"apdate": "01-02-2021", "booked": "10:00", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}, 
{"apdate": "01-02-2021", "booked": "03:30", "name": "Anand", "uuid": "cPA7ND7U2jdw7qY6nHf4kWuxyx53"}];

a = a.filter(obj => {
// add your date comparison logic here and return true for elements you want to keep
// in this example it will keep elements with '01-02-2021'
// you may add here your logic to compare dates
return obj.apdate === '01-02-2021';
})
// now this way you have cleared elements from a
console.log(a);