wait_for"reaction_add"检查不起作用

Question

我正在做一个命令，你需要用表情符号确认一些东西。我有一个wait_for("reaction_add")，检查作为lambda函数。

下面的代码是:

try:
reaction, user = await self.client.wait_for("reaction_add",
check=lambda react, usr: str(reaction.emoji) == "✅" and usr.id == ctx.author.id, timeout=60)
print(reaction.emoji)
except asyncio.TimeoutError:
await confirm_msg.edit(content="This message has timed out!", embed=None)

但是它不会打印出反应的表情符号。没有检查代码也能正常工作，所以它必须与检查有关。我怎样才能修好它呢?

谢谢!

Answer 1

Alambda函数本质上与普通函数相同。

λ:

lambda react, usr: str(reaction.emoji) == "✅" and usr.id == ctx.author.id

等于定义以下函数:

# Here we are within the wait_for(reaction_add)
def f(react, usr):
return str(reaction.emoji) == "✅" and user.id == ctx.author.id
# Rest of the code

问题是reaction_add没有定义react或usr。解决您的代码的方法是这样的:

reaction, user = await self.client.wait_for("reaction_add", check=lambda reaction,
user: str(reaction.emoji) == "✅" and user.id == ctx.author.id, timeout=60)

Answer 2

try:
reaction, user = await self.client.wait_for("reaction_add",
check=lambda reaction, user: str(reaction.emoji) == "✅" and user.id == ctx.author.id, timeout=60)
print(reaction.emoji)
except asyncio.TimeoutError:
await confirm_msg.edit(content="This message has timed out!", embed=None)

Answer 3

您可以尝试不使用lambda函数:

@client.event
async def on_raw_reaction_add(payload):
reaction = str(payload.emoji)
if reaction == "✅" and usr.id == ctx.author.id:
print('do something')
else:
print('something else')