在另一个定义中调用定义时不会运行

Question

我有一款游戏，要求用户猜1-100之间的一个数字，游戏会一直进行下去，当猜到最后时，它会询问用户是否想再玩一次。但是，当用户说"是"时，游戏不会再运行。

我已经按照这个顺序定义了游戏和结局，但是当用户说"是"时，游戏将不会再次播放，即使我已经这样做了，所以游戏正在被调用。

代码:

import random
import time
# Generate a random number between 1 and 100
secret_number = random.randint(1, 100)
# Set the maximum number of guesses
max_guesses = 5
# Initialize the number of guesses the player has made
guesses_made = 0


# Start the game loop
def game():

global secret_number
global max_guesses
global guesses_made

while guesses_made < max_guesses:
# Get the player's guess
guess = int(input("Enter your guess: "))
# Increment the number of guesses the player has made
guesses_made += 1
# Check if the player's guess is correct
if guess == secret_number:
print("You guessed the correct number! You win!")
break
# Check if the player's guess is too high
elif guess > secret_number:
print("Your guess is too high. Try again.")
# The player's guess must be too low
elif guess < secret_number:
print("Your guess is too low. Try again.")
# The player has run out of guesses
if guess != secret_number and guesses_made == max_guesses:
print("You have run out of guesses. The secret number was", secret_number)


def end():

print("Play again?")

user = input()

if user.casefold() == "yes":
print("okay!")
game()

elif user.casefold() == "no":
print("okay, goodbye!")

else:
print("That's not an option. Please say yes or no.")
time.sleep(1)
print ("Do you want to play again?")
user = input()

if user == "yes":
print("okay!")

print()
game()
elif user == "no":
print("okay, goodbye!")



# Explain the game to player
print ("Hello player, let's play a guessing game.")
time.sleep(1.5)
print ("I will pick a number between 1-100 and you have to try to guess it.")
time.sleep(1.5)
print()
print ("I will give you five chances to guess the number. If you guess correctly I will give you a treat. If at the end you still cannot guess the number then I will tell you and we will play again.")
time.sleep(2)
print()
print ("I hope you are ready!")
time.sleep(.5)
print ("Ready...")
time.sleep(.25)
print ("Set...")
time.sleep(.25)
print ("GUESS!!!")
print()
game()
end()

我试着重新定义游戏，但它只是玩游戏没有运行的开始。我也试过使其全局，但随后由于()的错误。

Answer 1

不是它不起作用，而是你已经猜不出来了。您需要在每次调用game()时重新初始化猜测次数和随机数。

。与其使用全局变量，不如将它们设置为game()函数的局部变量，并在其中初始化它们。它们不应该是全局的，因为它们在game()函数之外没有用处。

Answer 2

问题出在全局变量guesses_made。

有两种情况可以让你有一个更清晰的画面:

场景1:用户用完了所有的猜测。

变量guesses_made已经是5，并且一旦您再次运行函数game()，它将转到语句if guess != secret_number and guesses_made == max_guesses。因此游戏将自动停止。

场景2:用户永远不会用完所有的猜测。

让变量guesses_made = 2。(只是一个随机数字，幸运的玩家!)然后当你选择"是"时;再玩一次，你将能够再玩一次，但有3次机会。因为您没有将变量重置为0

还有一个边注:

因为你没有循环，它最多只能让玩家玩两次。