我可以使用Javascript来检测用户是否在另一个打开的选项卡上，而不是我的网站上吗

Question

我想知道用户当前是否在另一个打开的浏览器选项卡上处于活动状态，而不是在我的网站上进行交互。通过这种方式，我可以使用Javascript将新颖的HTML写入DOM。

Answer 1

可见性API-MDN

MDN示例

// Set the name of the hidden property and the change event for visibility
var hidden, visibilityChange;
if (typeof document.hidden !== "undefined") { // Opera 12.10 and Firefox 18 and later support
hidden = "hidden";
visibilityChange = "visibilitychange";
} else if (typeof document.msHidden !== "undefined") {
hidden = "msHidden";
visibilityChange = "msvisibilitychange";
} else if (typeof document.webkitHidden !== "undefined") {
hidden = "webkitHidden";
visibilityChange = "webkitvisibilitychange";
}
var videoElement = document.getElementById("videoElement");
// If the page is hidden, pause the video;
// if the page is shown, play the video
function handleVisibilityChange() {
if (document[hidden]) {
videoElement.pause();
} else {
videoElement.play();
}
}
// Warn if the browser doesn't support addEventListener or the Page Visibility API
if (typeof document.addEventListener === "undefined" || hidden === undefined) {
console.log("This demo requires a browser, such as Google Chrome or Firefox, that supports the Page Visibility API.");
} else {
// Handle page visibility change
document.addEventListener(visibilityChange, handleVisibilityChange, false);
// When the video pauses, set the title.
// This shows the paused
videoElement.addEventListener("pause", function(){
document.title = 'Paused';
}, false);
// When the video plays, set the title.
videoElement.addEventListener("play", function(){
document.title = 'Playing';
}, false);
}