使用Python中的dictionary替换列表中的字符串

Question

如何使用字典替换列表中的字符串？

我有

text = ["h#**o+","+&&&orld"]

replacement = {"#":"e","*":"l","+":"w","&":""}

我想要：

correct = ["Hellow 
World"]

我试过了：

def correct(text,replacement):
for word, replacement in replacement.items():
text = text.replace(word, replacement)

但是：AttributeError:"list"对象没有属性"replace">

Answer 1

除了correct函数似乎只想纠正一个str(例如"h#**o+"=>"hellow"(，而变量text当前是list或strs之外，您所拥有的基本都是正确的。因此，如果您想获得"hellow world"，您需要多次调用correct来获得一个已纠正单词的列表，然后可以将其连接到一个字符串中。

试试这个可运行的例子！

#!/usr/bin/env python
words = ["h#**o+","+&&&orld"]
replacement = {"#":"e","*":"l","+":"w","&":""}
def correct(text,replacement):
for word, replacement in replacement.items():
text = text.replace(word, replacement)
return text
def correct_multiple(words, replacement):
new_words = [correct(word, replacement) for word in words] # get a list of results
combined_str = " ".join(new_words) # join the list into a string
return combined_str
output = correct_multiple(words, replacement)
print(f"{output=}")

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Answer 2

您也可以这样做：

text = ["h#**o+","+&&&orld"]
replacement = {"#":"e","*":"l","+":"w","&":""}
string1 = " ".join(text)  # join the words into one string
string2 = string1.translate(string1.maketrans(replacement))
string3 = string2.title()
print(string1 + 'n' + string2 + 'n' + string3)
# h#**o+ +&&&orld
# hellow world
# Hellow World

我将程序分为三个连续的步骤，以展示每个步骤的效果。

Answer 3

text是字符串列表，而不是字符串。你不能在上面调用字符串方法。

text[0].replace()将是一件。。。