swagger core v3忽略我在javax.ws.rs.core.Application中的配置

Question

使用swagger core v2.1.6，这三种配置产生相同的openapi.json结果。

无配置：

@ApplicationPath("/rest")
public class AuthRestConfig extends Application {
public AuthRestConfig() {
}
}

服务器配置，我需要使用这种conf:

@ApplicationPath("/rest")
public class AuthRestConfig extends Application {
public AuthRestConfig(@Context ServletConfig servletConfig) {
super();
OpenAPI oas = new OpenAPI();
Info info = new Info()
.title("Suma Automaton OpenAPI")
.description("This is a sample server Petstore server.  You can find out more about Swagger "
+ "at [http://swagger.io](http://swagger.io) or on [irc.freenode.net, #swagger](http://swagger.io/irc/).  For this sample, "
+ "you can use the api key `special-key` to test the authorization filters.")
.termsOfService("http://swagger.io/terms/")
.contact(new Contact()
.email("[e-mail]"));
oas.info(info);
String url = "/suma-automaton-ms";
List<Server> servers = new ArrayList<>();
Server server = new Server();
server.setUrl(url);
servers.add(server);
oas.setServers(servers);
SwaggerConfiguration oasConfig = new SwaggerConfiguration()
.openAPI(oas)
.prettyPrint(true)
.resourcePackages(Stream.of("io.swagger.sample.resource").collect(Collectors.toSet()));
try {
new JaxrsOpenApiContextBuilder<>()
.servletConfig(servletConfig)
.application(this)
.openApiConfiguration(oasConfig)
.buildContext(true);
} catch (OpenApiConfigurationException e) {
throw new RuntimeException(e.getMessage(), e);
}
}
}

对这种行为有什么建议吗？有什么我误解了吗？假设我也使用中报告的标准配置有相同的行为https://github.com/swagger-api/swagger-core/wiki/Swagger-2.X---Integration-and-configuration#jax-rs应用程序

Answer 1

将其添加到AuthRestConfig类：

import io.swagger.v3.jaxrs2.integration.resources.OpenApiResource;
@Override
public Set<Class<?>> getClasses() {
Set<Class<?>> resources = new HashSet<>();
resources.add(OpenApiResource.class);
return resources;
}