None值Coalesce的Django方法。
我想每周查询问题的组计数。
query1 = MyModel.object.filter(issue_creator__in=group.user_set.all()).
annotate(week=TruncWeek('issue_creat_date')).values('week').annotate(count=Count('id')).order_by('week'))
查询结果正常。查询集结果:
[
{'week': datetime.datetime(2022, 1, 3, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 9},
{'week': datetime.datetime(2022, 1, 10, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 12},
{'week': datetime.datetime(2022, 1, 17, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 10},
{'week': datetime.datetime(2022, 2, 7, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 1},
{'week': datetime.datetime(2022, 2, 14, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 6},
{'week': datetime.datetime(2022, 2, 21, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 11},
{'week': datetime.datetime(2022, 2, 28, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 1}
]
但20220101-20220301有9周:
[
datetime.datetime(2022, 1, 3, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 1, 10, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 1, 17, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 1, 24, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 1, 31, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 2, 7, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 2, 14, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 2, 21, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>),
datetime.datetime(2022, 2, 28, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>)
]
当那周没有结果时,我想加零作为这个结果:
[
{'week': datetime.datetime(2022, 1, 3, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 9},
{'week': datetime.datetime(2022, 1, 10, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 12},
{'week': datetime.datetime(2022, 1, 17, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 10},
{'week': datetime.datetime(2022, 1, 24, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 0},
{'week': datetime.datetime(2022, 1, 31, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 0},
{'week': datetime.datetime(2022, 2, 7, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 1},
{'week': datetime.datetime(2022, 2, 14, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 6},
{'week': datetime.datetime(2022, 2, 21, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 11},
{'week': datetime.datetime(2022, 2, 28, 0, 0, tzinfo=<DstTzInfo 'Europe/Stockholm' CEST+2:00:00 DST>), 'count': 1}
]
如何编写正确的查询集?
谢谢。
from django.db.models.functions import Coalesce
query1 = MyModel.object.filter(issue_creator__in=group.user_set.all()).
annotate(week=TruncWeek('issue_creat_date')).values('week').annotate(count=Count('id')).order_by('week'))