检查字符串后面的版本号，如果没有找到版本号则出现错误

Question

目前正在寻找更好的方法…

例如，我有一个文件，其中包含一个分支名称或版本号的字符串。我想知道文件是否在ref模式之后没有使用版本号。

示例文件:

source = "git::https://URL?ref=main"
source = "git::https://URL?ref=0.1.0"

目前我是这样做的:

# Search for string after pattern and turn it into an array.
version=($(grep -oP '(?<=ref=).*' file.txt | tr -d '".'))
# If array does not contain number pattern, catch it.
if [[ $version =~ ^[0-9]+(.[0-9]+){2,3}$ ]]
then
echo "All module sources contain versions, will continue"
else
echo "Some module sources DO NOT contain versions, you must use a version number in your module source"
fi

我怎么能做到这一点与grep单独，甚至不得不导出字符串到数组?

Answer 1

最后是

if [[ $(grep -oPr '(?<=ref=).*' | tr -d '"') =~ ^[0-9]+(.[0-9]+){2,3}$ ]]
then
echo "All module sources contain versions, will continue"
else
echo "Some module sources DO NOT contain versions, you must use a version number in your module source"
fi

Answer 2

对于GNUgrep和PCRE正则表达式，您可以使用

#!/bin/bash
rx='ref=(?![0-9]+(.[0-9]+){2,3}")[^"]*"'
if grep -Pq "$rx" file.txt; then
echo "Some module sources DO NOT contain versions, you must use a version number in your module source"
else
echo "All module sources contain versions, will continue"
fi

参见在线演示。正则表达式的意思是

• ref=- aref=text
• (?![0-9]+(.[0-9]+){2,3}")-如果有一个或多个数字后面出现两次或三次点和一个或多个数字，则会导致匹配失败
• [^"]*"- 0个或多个"以外的字符，然后是"字符。

Answer 3

if grep -E 'ref=[0-9].[0-9]{2,3}$' file.txt; then
echo has version
else
echo has no version

Answer 4

Grep有一个--invert-match选项(又名-v)，所以您可以查找不匹配您的模式的行，如果搜索成功，您将知道您有不兼容的行:

if grep -vqE 'ref=d+(.d+)*"' file.txt; then
echo "Some module sources DO NOT contain versions, you must use a version number in your module source"
else
echo "All module sources contain versions, will continue"
fi