应用程序在另一个请求中发出请求后变慢

Question

我正在使用基于用户名的协程请求，它返回Object<Profile>的列表，并且有了该列表，我正在对每个对象进行另一个请求，然后切换并将信息传递到另一个屏幕，但是这样的过程使应用程序超级慢，我想找到一个更好的方法或一种方法来不使这个过程如此缓慢。这里是我的代码

片段，从我开始的过程，哪里的应用程序变得超级慢

emptyHomeViewModel.getPlayersListByName(text)
emptyHomeViewModel.listOfPlayersByNameLiveData.observe(viewLifecycleOwner) { playersByName ->
emptyHomeViewModel.getPlayersProfileByName(playersByName)
emptyHomeViewModel.listOfProfilesByID.observe(viewLifecycleOwner) { profiles ->
if (profiles != null) {
val list: Array<Profile> = profiles.toTypedArray()
bundle = Bundle().apply {
putSerializable("user", list)
}
findNavController().navigate(
R.id.action_emptyHomeFragment_to_selectUserFragment,
bundle
)
}
}
}

ViewModel，我从那里执行协程并向API发出请求

fun getPlayersListByName(playerName: String) = viewModelScope.launch {
val playersList = getPlayersByPersonaNameUseCase.getPlayersByName(playerName)
if (playersList != null) {
_listOfPlayersByNameLiveData.postValue(playersList)
}
}

fun getPlayersProfileByName(playersByName: List<PlayerByPersonaNameItem>?) =
viewModelScope.launch {
var playersProfileList: ArrayList<Profile> = arrayListOf()
if (playersByName != null) {
for (player in playersByName) {
getPlayerByIDUseCase.getPlayerById(player.accountId)
?.let { playersProfileList.add(it) }
}
_listOfProfilesByID.postValue(playersProfileList)
}
}

Answer 1

你实际上可以并行加载配置文件，防止一个接一个地加载它们，以减少加载数据的时间:

fun getPlayersProfileByName(playersByName: List<PlayerByPersonaNameItem>?) =
viewModelScope.launch {
val playersProfileList: List<Profile> = playersByName?.map { player ->
async {
getPlayerByIDUseCase.getPlayerById(player.accountId)
}
}.awaitAll().filterNotNull()
_listOfProfilesByID.postValue(playersProfileList)
}

你也可以通过移除额外的LiveData观察者并在你得到playersList之后调用getPlayersProfileByName来改进它:

fun getPlayersListByName(playerName: String) = viewModelScope.launch {
val playersList = getPlayersByPersonaNameUseCase.getPlayersByName(playerName)
getPlayersProfileByName(playersList)
}