"Stuff 和 'For Xml 路径'"或 UNION 排除重复行

Question

这是问题的进一步进展:如何使用"Stuff和'For Xml Path'"统一表

中的行我有3个表-发票，位置和帐户，这些表通过SELECT构建公共表，如下面的结果所示。我需要排除由于相同发票的不同帐户而出现的重复行。我认为它可以通过"Stuff和'For Xml Path'"和/或UNION来解决，但我真的不知道如何做到这一点。

请协助解决这个问题。提前谢谢你。

下面是DL和样本数据填充的dbfiddle: https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=6401c2886a24b21239dade27e8c549ec

使用基于SQL Server 2016的DevExpress仪表板设计器

查询:

-- DDL and sample data population, start
CREATE TABLE invoices
(
invoice VARCHAR(20) NOT NULL,
id INT NOT NULL,
);
INSERT invoices(invoice, id) 
VALUES ('ty20210110', 1);
INSERT invoices(invoice, id) 
VALUES ('ty20210111', 2);
INSERT invoices(invoice, id) 
VALUES ('ty20210112', 3);
CREATE TABLE positions
(
position VARCHAR(20) NOT NULL,
quantity INT NOT NULL,
price INT NOT NULL,
summ INT NOT NULL, 
invoice INT NOT NULL,
);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000001', 2, 100, 200, 1);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000002', 3, 100, 300, 2);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000003', 1, 250, 250, 2);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000004', 2, 120, 240, 1);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000005', 4, 100, 400, 1);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000006', 3, 100, 300, 1001);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000007', 5, 80, 400, 3);
INSERT positions(position, quantity, price, summ, invoice) 
VALUES ('p1000008', 5, 100, 500, 3);
CREATE TABLE accounts
(
account INT NOT NULL,
invoice INT NOT NULL,
);
INSERT accounts(account, invoice) 
VALUES (01, 2);
INSERT accounts(account, invoice) 
VALUES (02, 2);
INSERT accounts(account, invoice) 
VALUES (03, 1);
INSERT accounts(account, invoice) 
VALUES (04, 3);
INSERT accounts(account, invoice) 
VALUES (05, 1);
INSERT accounts(account, invoice) 
VALUES (06, 3);
-- DDL and sample data population, end

SELECT
positions.position, positions.quantity, positions.price, positions.summ,
invoices.invoice,
accounts.account
FROM
positions
INNER JOIN
invoices invoices ON invoices.id = positions.invoice
INNER JOIN
accounts accounts ON invoices.id = accounts.invoice

结果:

<表类>位置数量价格夏发票账户tbody><<tr>p10000012100200in202101103p10000012100200in202101105p10000023100300in202101111p10000023100300in202101112p10000031250250in202101111p10000031250250in202101112p10000042120240in202101103p10000042120240in202101105p10000054100400in202101103p10000054100400in202101105p10000063100300in202101103p10000063100300in202101105p1000007580400in202101124p1000007580400in202101126p10000085100500in202101124p10000085100500in202101126

你的第一个结果集可以用两种方式处理，这取决于你的SQL Server版本。在SSMS中尝试以下示例:

创建数据

DECLARE @invoices table (
invoice VARCHAR(20) NOT NULL, id INT NOT NULL 
);
INSERT INTO @invoices (invoice, id) VALUES 
( 'ty20210110', 1 ), ( 'ty20210111', 2 ), ( 'ty20210112', 3 );
DECLARE @positions table (
position VARCHAR(20) NOT NULL, quantity INT NOT NULL, price INT NOT NULL, summ INT NOT NULL, invoice INT NOT NULL
);
INSERT INTO @positions ( position, quantity, price, summ, invoice ) VALUES
( 'p1000001', 2, 100, 200, 1 ),
( 'p1000002', 3, 100, 300, 2 ),
( 'p1000003', 1, 250, 250, 2 ),
( 'p1000004', 2, 120, 240, 1 ),
( 'p1000005', 4, 100, 400, 1 ),
( 'p1000006', 3, 100, 300, 1 ),
( 'p1000007', 5, 80, 400, 3 ),
( 'p1000008', 5, 100, 500, 3 );
DECLARE @accounts table (
account INT NOT NULL, invoice INT NOT NULL
);
INSERT INTO @accounts ( account, invoice ) VALUES 
( 1, 2 ), ( 2, 2 ), ( 3, 1 ), ( 4, 3 ), ( 5, 1 ), ( 6, 3 );

如果你正在使用SQL Server 2017+

SELECT
positions.position,
positions.quantity,
positions.price,
positions.summ,
invoices.invoice,
STRING_AGG ( accounts.account, ',' ) AS account
FROM @positions positions
INNER JOIN @invoices invoices 
ON invoices.id = positions.invoice
INNER JOIN @accounts accounts 
ON invoices.id = accounts.invoice
GROUP BY
position, quantity, price, summ, invoices.invoice
ORDER BY
invoice;

Pre-SQL Server 2017

SELECT
positions.position,
positions.quantity,
positions.price,
positions.summ,
invoices.invoice,
acct.account
FROM @positions positions
INNER JOIN @invoices invoices 
ON invoices.id = positions.invoice
INNER JOIN @accounts accounts 
ON invoices.id = accounts.invoice
OUTER APPLY (
SELECT STUFF ( (
SELECT ',' + CAST ( a.account AS varchar(50) ) AS "text()"
FROM @accounts a
WHERE
a.invoice = invoices.id
FOR XML PATH ( '' )
), 1, 1, '' ) AS account
) AS acct
GROUP BY
position, quantity, price, summ, invoices.invoice, acct.account
ORDER BY
invoice;

两个查询都返回

+----------+----------+-------+------+------------+---------+
| position | quantity | price | summ |  invoice   | account |
+----------+----------+-------+------+------------+---------+
| p1000001 |        2 |   100 |  200 | ty20210110 | 3,5     |
| p1000004 |        2 |   120 |  240 | ty20210110 | 3,5     |
| p1000005 |        4 |   100 |  400 | ty20210110 | 3,5     |
| p1000006 |        3 |   100 |  300 | ty20210110 | 3,5     |
| p1000002 |        3 |   100 |  300 | ty20210111 | 1,2     |
| p1000003 |        1 |   250 |  250 | ty20210111 | 1,2     |
| p1000007 |        5 |    80 |  400 | ty20210112 | 4,6     |
| p1000008 |        5 |   100 |  500 | ty20210112 | 4,6     |
+----------+----------+-------+------+------------+---------+

您请求的第二个结果集要复杂得多，需要使用XML数据类型。下面的示例对您的数据进行了自由的假设，最值得注意的是，只需要两个帐户。话虽如此，您可以根据需要在PIVOT中扩展[account n]列，而不必诉诸动态SQL。

SELECT DISTINCT
positions.position,
positions.quantity,
positions.price,
positions.summ,
invoices.invoice
, x.*
FROM @positions positions
INNER JOIN @invoices invoices 
ON invoices.id = positions.invoice
INNER JOIN @accounts accounts 
ON invoices.id = accounts.invoice
OUTER APPLY (
-- Create an XML account list --
SELECT CAST ( (
SELECT 
'account ' + CAST ( ROW_NUMBER() OVER ( ORDER BY a.invoice ) AS varchar(50) ) AS id,
a.account
FROM @accounts a
WHERE
a.invoice = invoices.id
FOR XML PATH ( 'data' ), ROOT ( 'accounts' )
) AS xml ) AS account_xml
) AS acct
OUTER APPLY (
-- PIVOT the account details --
SELECT
*
FROM (
SELECT
x.f.value( 'id[1]', 'varchar(50)' ) AS id,
x.f.value( 'account[1]', 'varchar(50)' ) AS act
FROM acct.account_xml.nodes( '//accounts/data' ) x(f)
) AS d
PIVOT (
MAX ( act ) FOR id IN ( [account 1], [account 2] )
) AS p
) AS x
ORDER BY
invoice;

返回

+----------+----------+-------+------+------------+-----------+-----------+
| position | quantity | price | summ |  invoice   | account 1 | account 2 |
+----------+----------+-------+------+------------+-----------+-----------+
| p1000001 |        2 |   100 |  200 | ty20210110 |         3 |         5 |
| p1000004 |        2 |   120 |  240 | ty20210110 |         3 |         5 |
| p1000005 |        4 |   100 |  400 | ty20210110 |         3 |         5 |
| p1000006 |        3 |   100 |  300 | ty20210110 |         3 |         5 |
| p1000002 |        3 |   100 |  300 | ty20210111 |         1 |         2 |
| p1000003 |        1 |   250 |  250 | ty20210111 |         1 |         2 |
| p1000007 |        5 |    80 |  400 | ty20210112 |         4 |         6 |
| p1000008 |        5 |   100 |  500 | ty20210112 |         4 |         6 |
+----------+----------+-------+------+------------+-----------+-----------+