从文件中获取字符串和整数C++的输入

Question

我有一个文本文件。我有一个由成员数据组成的文本文件。我正在开发一个程序，我们可以从文件中获取成员数据。在互联网上搜索后，我找到了一种方法，以char数组的形式读取文件中的所有数据。但我想更改它，在读取文件时，我希望数据是字符串和整数。

1. 姓名、icno、电子邮件、电话号码、账号、密码(从文件中读取为字符串)
2. 月，年(从文件AS INTEGER中读取)

Membership.txt 的内容

Mathavan|021127100897|[e-mail]|0167750575|1410065449|Mathavan1234|3|2022
Mathavan|021127100897|[e-mail]|0167750575|1410065448|Mathavan1234|3|2024
Mathavan|021127100897|[e-mail]|0167750575|1410065447|Mathavan1234|3|2022

string member_login(){
title();
fstream member;
member.open("Membership.txt",ios::in);
string pass_input, line, acc_num1, password1;
int login_attempt = 0, count = 0 , account = 0;
char dummy, resp, accno_input[25], name[25], icno[25],email [40], phone_number[25],acc_num[25],password[25],month[25], year[25];
account_num:
cout << "                                          Enter your account number : ";
cin >> accno_input;
ifstream file("Membership.txt");
while (!file.eof()){
getline(file, line);
count++;
}
cout << accno_input;
int i = 0;
while(i <= count)
{
member.getline(name,25,'|');
member.getline(icno,25,'|');
member.getline(email,40,'|');
member.getline(phone_number,25, '|');
member.getline(acc_num,25, '|');
member.getline(password,25,'|' );
member.getline(month,25,'|' );
member.getline(year, 25);
cout << name << " ";
cout << icno << " ";
cout << acc_num << " ";
cout << accno_input;
if (acc_num == accno_input){
account = 1;
break;
}
i ++;
}
cout << account;
member.close();
if ( account != 1 ){
cout << endl;
cout << "                                  Your account not found !!!"<< endl;
cout << "                                  Please try again !!" << endl << endl;
cout << "                                  PLEASE ENTER ANY KEY TO CONTINUE >>> ";
cin >> dummy;
goto account_num;
}
password1 = password;
cout << endl;
cout << "                                          Enter your account password : ";
cin >> pass_input;
for (login_attempt = 1 ; login_attempt <= 2 ; login_attempt ++){
if (pass_input == password1){
cout << "Login Successful !!!";
break;
}
cout << endl;
cout << "Login Failed. Attempt " << login_attempt  << " of 3" << endl;
cout << "Please re-enter Password: " ;
cin >> pass_input;
if (pass_input == password1){
cout << "Login Successful !!!";
break;
}
}
if ( login_attempt == 3){
cout << endl;
cout << "Login Failed. Attempt 3 of 3";
}
return accno_input;
}

Answer 1

您的程序中有太多完全错误的地方，我建议您：

删除并从头开始。

没有可能的有意义的解决方案。甚至还有一个goto。并且你必须停止在C++中使用具有某些agic维度的C样式数组。C++有很多东西可以让你的生活更轻松。只需使用它们。

请在下面找到一个C++解决方案。

你可以复制粘贴它并保持原样，或者，你花3个小时在谷歌上搜索所有结构，努力理解和学习，成为一名更好的程序员。你的选择。

#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
#include <vector>
#include <regex>
#include <iterator>
#include <algorithm>
const std::regex re{ R"(|)" };
struct Member {
// Memeber data
std::string name{};
std::string icno{};
std::string email{};
std::string phoneNumber{};
std::string accountNumber{};
std::string password{};
int month{};
int year{};
// Extractor operator
friend std::istream& operator >> (std::istream& is, Member& m) {
// Readone complete line
if (std::string line{}; std::getline(is, line)) {
// Split it into parts
std::vector parts(std::sregex_token_iterator(line.begin(), line.end(), re, -1), {});
// assign parts to member data
if (parts.size() == 8) {
m.name = parts[0]; m.icno = parts[1]; m.email = parts[2]; m.phoneNumber = parts[3]; m.accountNumber = parts[4]; m.password = parts[5];
m.month = std::stoi(parts[6]); m.year = std::stoi(parts[7]);
}
}
return is;
}
};
// Filename for member data
const std::string fileName{ "r:\Membership.txt" };
int main() {
// Open the data file and check, if it could be opened
if (std::ifstream fileStream{ fileName }; fileStream) {
// Read complete source file, parse it and get all data
std::vector memberData(std::istream_iterator<Member>(fileStream), {});
// We want the user to give 3 trials to enter valid data
constexpr unsigned int MaxTrials = 3u;
unsigned int numberOfTrials{}; 
// A valid input will stop the loop immediately
bool validInputgiven{};
// Now, try to get the correct input
while (not validInputgiven and numberOfTrials < MaxTrials) {
// Get an acoount number
std::cout << "nEnter a account number: ";
std::string account{};
std::cin >> account;
// Check, if the account number is in the member data
if (std::count_if(memberData.begin(), memberData.end(), [&](const Member& m) { return m.accountNumber == account; }) > 0) {
// Account info wasOK. Get the password
std::cout << "nEnter your password: ";
std::string password{};
std::cin >> password;
if (std::count_if(memberData.begin(), memberData.end(), [&](const Member& m) { return m.accountNumber == account and m.password == password; }) > 0) {
// Valid data found
validInputgiven = true;
std::cout << "nnEverything OK. Data validated.nn";
}
}
// Next try
++numberOfTrials;
if (not validInputgiven and numberOfTrials < MaxTrials) std::cout << "nInvalid input. Please try againnnn";
}
if (not validInputgiven ) std::cout << "nToo many wrong tries. Aborting . . .nnn";
}
else std::cerr << "nnError. Could not open source file '" << fileName << "'nn";
}